刪除List中重復元素
方法一:循環元素刪除// 刪除ArrayList中重復元素
public static void removeDuplicate(List list) {
for (int i = 0; i < list.size() - 1; i++) {
for (int j = list.size() - 1; j > i; j--) {
if (list.get(j).equals(list.get(i))) {
list.remove(j);
}
}
}
System.out.println(list);
}
public static void removeDuplicate(List list) {
for (int i = 0; i < list.size() - 1; i++) {
for (int j = list.size() - 1; j > i; j--) {
if (list.get(j).equals(list.get(i))) {
list.remove(j);
}
}
}
System.out.println(list);
}
方法二:通過HashSet剔除
// 刪除ArrayList中重復元素
public static void removeDuplicate(List list) {
Set set = new HashSet(list);
list.clear();
list.addAll(set);
System.out.println(list);
}
public static void removeDuplicate(List list) {
Set set = new HashSet(list);
list.clear();
list.addAll(set);
System.out.println(list);
}
方法三: 刪除ArrayList中重復元素,保持順序
// 刪除ArrayList中重復元素,保持順序
public static void removeDuplicateWithOrder(List list) {
Set set = new HashSet();
List newList = new ArrayList();
for (Iterator iter = list.iterator(); iter.hasNext();) {
Object element = iter.next();
if (set.add(element))
newList.add(element);
}
list.clear();
list.addAll(newList);
System.out.println(" remove duplicate " + list);
}
public static void removeDuplicateWithOrder(List list) {
Set set = new HashSet();
List newList = new ArrayList();
for (Iterator iter = list.iterator(); iter.hasNext();) {
Object element = iter.next();
if (set.add(element))
newList.add(element);
}
list.clear();
list.addAll(newList);
System.out.println(" remove duplicate " + list);
}
posted on 2014-08-18 12:09 paulwong 閱讀(1873) 評論(0) 編輯 收藏 所屬分類: J2SE