端口掃描程序
If you need 200ms for each of the 65536 ports (in the worst case, a firewall is blocking everything, thus making you hit your timeout for every single port), the maths is pretty simple: you need 13k seconds, or about 3 hours and a half.You have 2 (non-exclusive) options to make it faster:
- reduce your timeout
- paralellize your code
The easiest way (ie, with minimal changes) is to use the ExecutorService and Future APIs: @import url(http://www.aygfsteel.com/CuteSoft_Client/CuteEditor/Load.ashx?type=style&file=SyntaxHighlighter.css);@import url(/css/cuteeditor.css);
public static Future<Boolean> portIsOpen(final ExecutorService es, final String ip, final int port, final int timeout) {
return es.submit(new Callable<Boolean>() {
@Override public Boolean call() {
try {
Socket socket = new Socket();
socket.connect(new InetSocketAddress(ip, port), timeout);
socket.close();
return true;
} catch (Exception ex) {
return false;
}
}
});
}
return es.submit(new Callable<Boolean>() {
@Override public Boolean call() {
try {
Socket socket = new Socket();
socket.connect(new InetSocketAddress(ip, port), timeout);
socket.close();
return true;
} catch (Exception ex) {
return false;
}
}
});
}
Then, you can do something like:
public static void main(final String
args) {
final ExecutorService es = Executors.newFixedThreadPool(20);
final String ip = "127.0.0.1";
final int timeout = 200;
final List<Future<Boolean>> futures = new ArrayList<>();
for (int port = 1; port <= 65535; port++) {
futures.add(portIsOpen(es, ip, port, timeout));
}
es.shutdown();
int openPorts = 0;
for (final Future<Boolean> f : futures) {
if (f.get()) {
openPorts++;
}
}
System.out.println("There are " + openPorts + " open ports on host " + ip + " (probed with a timeout of " + timeout + "ms)");
}

final ExecutorService es = Executors.newFixedThreadPool(20);
final String ip = "127.0.0.1";
final int timeout = 200;
final List<Future<Boolean>> futures = new ArrayList<>();
for (int port = 1; port <= 65535; port++) {
futures.add(portIsOpen(es, ip, port, timeout));
}
es.shutdown();
int openPorts = 0;
for (final Future<Boolean> f : futures) {
if (f.get()) {
openPorts++;
}
}
System.out.println("There are " + openPorts + " open ports on host " + ip + " (probed with a timeout of " + timeout + "ms)");
}
If you need to know which ports are open (and not just how many, as in the above example), you'd need to change the return type of the function to Future<SomethingElse>, where SomethingElse would hold the port and the result of the scan, something like:
public final class ScanResult {
private final int port;
private final boolean isOpen;
// constructor
// getters
}
private final int port;
private final boolean isOpen;
// constructor
// getters
}
Then, change Boolean to ScanResult in the first snippet, and return new ScanResult(port, true) or new ScanResult(port, false) instead of just true or false
posted on 2013-03-14 10:10 paulwong 閱讀(381) 評論(0) 編輯 收藏 所屬分類: 性能優化