Decode360's Blog

          業精于勤而荒于嬉 QQ:150355677 MSN:decode360@hotmail.com

            BlogJava :: 首頁 :: 新隨筆 :: 聯系 ::  :: 管理 ::
            397 隨筆 :: 33 文章 :: 29 評論 :: 0 Trackbacks
          PLSQL算24點
          ?
          ?
          ??? 很早以前就想用PLSQL寫一個算24點的程序了,后來想了一下沒有研究下去,最近上ITPUB的時候正好大家都在討論,在大牛的基礎上修改了一下,基本上思想和算法都是沒有變的,就是學習了一下。還有兩個大問題沒有處理好,一是只用了枚舉法,用PLSQL應該可以換個更好的遞歸算法的;二是沒有濾重;反正最后的結果只是最簡單的得到答案而已。
          ?
          ??? 具體的可以參見:
          ?
          ??? http://www.itpub.net/viewthread.php?tid=1061129&extra=page%3D1%26amp%3Bfilter%3Ddigest&page=1
          ??? http://www.itpub.net/viewthread.php?tid=1077244&extra=&page=1
          ?
          ?
          ?
          create or replace function f_op (p_n1 number, p_op varchar2, p_n2 number) return number
          as
          begin
          ?? return case when p_op = '+' then p_n1 + p_n2
          ?????????????? when p_op = '-' then p_n1 - p_n2
          ?????????????? when p_op = '*' then p_n1 * p_n2
          ?????????????? when p_op = '/' and p_n2<>0 then p_n1 / p_n2
          ?????????????? else null
          ????????? end;
          end f_op;
          /
          ?
          ?
          create or replace procedure pro_24(p1 number, p2 number, p3 number, p4 number) as
          ? r_result number default 0;
          begin
          ? for r in (
          ????? with t_num as
          ????????? (select 1 id,p1 as n from dual
          ?????????? union
          ?????????? select 2 id,p2 as n from dual
          ?????????? union
          ?????????? select 3 id,p3 as n from dual
          ?????????? union
          ?????????? select 4 id,p4 as n from dual),
          ?????????? t_op as
          ????????? (select '+' as o from dual
          ?????????? union
          ?????????? select '-' as o from dual
          ?????????? union
          ?????????? select '*' as o from dual
          ?????????? union
          ?????????? select '/' as o from dual)
          ?????? select distinct
          ????????????? a.n? as a,
          ????????????? o1.o as o1,
          ????????????? b.n? as b,
          ????????????? o2.o as o2,
          ????????????? c.n? as c,
          ????????????? o3.o as o3,
          ????????????? d.n? as d
          ???????? from t_num a, t_num b, t_num c, t_num d,
          ????????????? t_op? o1, t_op? o2, t_op? o3
          ??????? where a.id not in (b.id, c.id, d.id)
          ????????? and b.id not in (c.id, d.id)
          ????????? and c.id <> d.id) loop
          ?
          ?????? r_result := f_op(f_op(f_op(r.a,r.o1,r.b),r.o2,r.c),r.o3,r.d);
          ?????? if r_result between 23.9 and 24.1 then
          ?????? dbms_output.put_line('(('||r.a||r.o1||r.b||')'||r.o2||r.c||')'||r.o3||r.d);
          ?????? end if; --((a b) c) d
          ??????
          ?????? r_result := f_op(f_op(r.a,r.o1,f_op(r.b,r.o2,r.c)),r.o3,r.d);
          ?????? if r_result between 23.9 and 24.1 then
          ?????? dbms_output.put_line('('||r.a||r.o1||'('||r.b||r.o2||r.c||'))'||r.o3||r.d);
          ?????? end if; --(a (b c)) d
          ??????
          ?????? r_result := f_op(f_op(r.a,r.o1,r.b),r.o2,f_op(r.c,r.o3,r.d));
          ?????? if r_result between 23.9 and 24.1 then
          ?????? dbms_output.put_line('('||r.a||r.o1||r.b||')'||r.o2||'('||r.c||r.o3||r.d||')');
          ?????? end if; --(a b) (c d)
          ??????
          ?????? r_result := f_op(r.a,r.o1,f_op(f_op(r.b,r.o2,r.c),r.o3,r.d));
          ?????? if r_result between 23.9 and 24.1 then
          ?????? dbms_output.put_line(r.a||r.o1||'(('||r.b||r.o2||r.c||')'||r.o3||r.d||')');
          ?????? end if; --a ((b c) d)
          ???????????
          ?????? r_result := f_op(r.a,r.o1,f_op(r.b,r.o2,f_op(r.c,r.o3,r.d)));
          ?????? if r_result between 23.9 and 24.1 then
          ?????? dbms_output.put_line(r.a||r.o1||'('||r.b||r.o2||'('||r.c||r.o3||r.d||'))');
          ?????? end if; --a (b (c d))
          ? end loop;
          end;
          /
          ?
          ?
          exec pro_24(3,3,8,8);
          ?
          posted on 2008-12-28 23:55 decode360 閱讀(159) 評論(0)  編輯  收藏 所屬分類: 06.PLSQL
          主站蜘蛛池模板: 藁城市| 宿州市| 商丘市| 扬州市| 普陀区| 句容市| 叙永县| 华容县| 北川| 安阳县| 体育| 游戏| 江阴市| 黄龙县| 雷山县| 三河市| 体育| 南和县| 黄浦区| 颍上县| 读书| 仁寿县| 合肥市| 乌拉特前旗| 高清| 鹤峰县| 华安县| 荃湾区| 云阳县| 临颍县| 松江区| 泸州市| 桓仁| 黑河市| 大姚县| 抚松县| 宜兴市| 阆中市| 临桂县| 丹巴县| 开阳县|