先寫一個(gè)測試程序來看看snapshot的使用:
#include "leveldb/db.h"
using namespace std;
using namespace leveldb;
int main() {
DB *db ;
Options op;
op.create_if_missing = true;
Status s = DB::Open(op,"/tmp/testdb",&db);
if(s.ok()){
cout << "create successfully" << endl;
s = db->Put(WriteOptions(),"abcd","1234");
if(s.ok()){
cout << "put successfully" << endl;
string value;
s = db->Get(ReadOptions(),"abcd",&value);
if(s.ok()){
cout << "get successfully,value:" << value << endl;
}
}
if(s.ok()){
string value;
const Snapshot * ss =db->GetSnapshot();
ReadOptions rop;
db->Put(WriteOptions(),"abcd","123456");
db->Get(rop,"abcd",&value);
if(s.ok()){
cout << "get successfully,value:" << value << endl;
}
rop.snapshot = ss;
db->Get(rop,"abcd",&value);
if(s.ok()){
cout << "get from snapshot successfully,value:" << value << endl;
}
db->ReleaseSnapshot(ss);
}
}
delete db;
return 0;
}
程序運(yùn)行的輸出結(jié)果是:
put successfully
get successfully,value:1234
get successfully,value:123456
get from snapshot successfully,value:1234
可以看出,即使在數(shù)據(jù)更新后,我們?nèi)匀豢梢詮膕napshot中讀到舊的數(shù)據(jù)。
下面我們來分析leveldb中snapshot的實(shí)現(xiàn)。
SequenceNumber(db/dbformat.h)
// We leave eight bits empty at the bottom so a type and sequence#
// can be packed together into 64-bits.
static const SequenceNumber kMaxSequenceNumber =
((0x1ull << 56) - 1);
SnapShot(db/snapshot.h),,可以看出snapshot其實(shí)就是一個(gè)sequence number
public:
//創(chuàng)建后保持不變
SequenceNumber number_;
private:
friend class SnapshotList;
//雙向循環(huán)鏈表
SnapshotImpl* prev_;
SnapshotImpl* next_;
SnapshotList* list_; // just for sanity checks
};
創(chuàng)建snapshot:
MutexLock l(&mutex_);
return snapshots_.New(versions_->LastSequence());
}
刪除snapshot:
MutexLock l(&mutex_);
snapshots_.Delete(reinterpret_cast<const SnapshotImpl*>(s));
}
posted @ 2012-03-13 16:54 小明 閱讀(4495) | 評論 (0) | 編輯 收藏