??xml version="1.0" encoding="utf-8" standalone="yes"?>国产精品免费久久,亚洲成人av在线播放,婷婷在线视频http://www.aygfsteel.com/nokiaguy/category/39413.htmlzh-cnSat, 02 Feb 2013 23:52:44 GMTSat, 02 Feb 2013 23:52:44 GMT60- 癑ֺ面试题:(x)求绝对值最的?/title>http://www.aygfsteel.com/nokiaguy/archive/2013/01/30/394920.html银河使?/dc:creator>银河使?/author>Wed, 30 Jan 2013 03:45:00 GMThttp://www.aygfsteel.com/nokiaguy/archive/2013/01/30/394920.htmlhttp://www.aygfsteel.com/nokiaguy/comments/394920.htmlhttp://www.aygfsteel.com/nokiaguy/archive/2013/01/30/394920.html#Feedback4http://www.aygfsteel.com/nokiaguy/comments/commentRss/394920.htmlhttp://www.aygfsteel.com/nokiaguy/services/trackbacks/394920.html 有一个已l排序的数组Q升序)Q数l中可能有正数、负数或0Q求数组中元素的l对值最的敎ͼ要求Q不能用序比较的方法(复杂度需要小于OQnQ)Q可以用Q何语a实现
例如Q数l{-20Q?13Q?4, 6, 77,200} Q绝对值最的?4?/p>
法实现的基本思\
扑ֈ负数和正数的分界点,如果正好?是它了Q如果是正数Q再和左面相?c)负数l对值比较,如果是负敎ͼ取取l对g右面正数比较。还要考虑数组只有正数或负数的情况?/p>
我根据这个思\用Java单实C一个算法?span style="color: #ff0000;">大家有更好的实现Ҏ(gu)Ƣ迎跟帖
public class MinAbsoluteValue
{
private static int getMinAbsoluteValue(int[] source)
{
int index = 0;
int result = 0;
int startIndex = 0;
int endIndex = source.length - 1;
// 计算负数和正数分界点
while(true)
{ // 计算当前的烦?/span>
index = startIndex + (endIndex - startIndex) / 2;
result = source[index];<br> // 如果{于0Q就直接q回了,0肯定是绝对值最的
if(result==0)
{
return 0;
} // 如果值大?Q处理当前位|左侧区域,因ؓ(f)负数肯定在左?/span>
else if(result > 0)
{
if(index == 0)
{
break;
}
if(source[index-1] >0)
endIndex = index - 1;
else if(source[index-1] ==0)
return 0;
else
break;
} // 如果于0Q处理当前位|右侧的区域Q因为正数肯定在右侧的位|?/span>
else
{
if(index == endIndex)
break;
if(source[index + 1] < 0)
startIndex = index + 1;
else if(source[index + 1] == 0)
return 0;
else
break;
}
}
// Ҏ(gu)分界点计绝对值最的?/span>
if(source[index] > 0)
{
if(index == 0 || source[index] < Math.abs(source[index-1]))
result= source[index];
else
result = source[index-1];
}
else
{
if(index == source.length - 1 || Math.abs(source[index]) < source[index+1])
result= source[index];
else
result = source[index+1];
}
return result;
}
public static void main(String[] args) throws Exception
{
int[] arr1 = new int[]{-23,-22,-3,-2,1,2,3,5,20,120};
int[] arr2 = new int[]{-23,-22,-12,-6,-4};
int[] arr3 = new int[]{1,22,33,55,66,333};
int value = getMinAbsoluteValue(arr1);
System.out.println(value);
value = getMinAbsoluteValue(arr2);
System.out.println(value);
value = getMinAbsoluteValue(arr3);
System.out.println(value);
}
}

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W?章:(x)开心桌面:(x)完全模拟Windows桌面的开心网
W?5章:(x)Ud?sh)子相册Q捕捉精彩瞬?
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adb kill-server
在关闭adb服务后,要用如下的命o启动adb服务?
adb start-server
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