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          CLASS 文件使用例子二

          Posted on 2012-04-15 16:27 zljpp 閱讀(142) 評(píng)論(0)  編輯  收藏

          ?

          上一節(jié)我看了一個(gè)簡(jiǎn)單的例子,我們通過(guò)直接改變二進(jìn)制的class文件,改變程序的行為,

          這一節(jié)繼續(xù)上面的例子看一些其他的情況,用前面的HelloWorld為例

          ?先看java 文件:

          ?

          ?

          public class HelloWorld{
          	public static void main(String [] arvgs){
          	  System.out.println("hello world");
          }
          }

          ?

          ?

          它的class文件

          ?

          ?

          00000000h: CA FE BA BE 00 00 00 2E 00 1D 0A 00 06 00 0F 09 ; 漱壕............
          00000010h: 00 10 00 11 08 00 12 0A 00 13 00 14 07 00 15 07 ; ................
          00000020h: 00 16 01 00 06 3C 69 6E 69 74 3E 01 00 03 28 29 ; .....<init>...()
          00000030h: 56 01 00 04 43 6F 64 65 01 00 0F 4C 69 6E 65 4E ; V...Code...LineN
          00000040h: 75 6D 62 65 72 54 61 62 6C 65 01 00 04 6D 61 69 ; umberTable...mai
          00000050h: 6E 01 00 16 28 5B 4C 6A 61 76 61 2F 6C 61 6E 67 ; n...([Ljava/lang
          00000060h: 2F 53 74 72 69 6E 67 3B 29 56 01 00 0A 53 6F 75 ; /String;)V...Sou
          00000070h: 72 63 65 46 69 6C 65 01 00 0F 48 65 6C 6C 6F 57 ; rceFile...HelloW
          00000080h: 6F 72 6C 64 2E 6A 61 76 61 0C 00 07 00 08 07 00 ; orld.java.......
          00000090h: 17 0C 00 18 00 19 01 00 0B 68 65 6C 6C 6F 20 77 ; .........hello w
          000000a0h: 6F 72 6C 64 07 00 1A 0C 00 1B 00 1C 01 00 0A 48 ; orld...........H
          000000b0h: 65 6C 6C 6F 57 6F 72 6C 64 01 00 10 6A 61 76 61 ; elloWorld...java
          000000c0h: 2F 6C 61 6E 67 2F 4F 62 6A 65 63 74 01 00 10 6A ; /lang/Object...j
          000000d0h: 61 76 61 2F 6C 61 6E 67 2F 53 79 73 74 65 6D 01 ; ava/lang/System.
          000000e0h: 00 03 6F 75 74 01 00 15 4C 6A 61 76 61 2F 69 6F ; ..out...Ljava/io
          000000f0h: 2F 50 72 69 6E 74 53 74 72 65 61 6D 3B 01 00 13 ; /PrintStream;...
          00000100h: 6A 61 76 61 2F 69 6F 2F 50 72 69 6E 74 53 74 72 ; java/io/PrintStr
          00000110h: 65 61 6D 01 00 07 70 72 69 6E 74 6C 6E 01 00 15 ; eam...println...
          00000120h: 28 4C 6A 61 76 61 2F 6C 61 6E 67 2F 53 74 72 69 ; (Ljava/lang/Stri
          00000130h: 6E 67 3B 29 56 00 21 00 05 00 06 00 00 00 00 00 ; ng;)V.!.........
          00000140h: 02 00 01 00 07 00 08 00 01 00 09 00 00 00 1D 00 ; ................
          00000150h: 01 00 01 00 00 00 05 2A B7 00 01 B1 00 00 00 01 ; .......*?.?...
          00000160h: 00 0A 00 00 00 06 00 01 00 00 00 01 00 09 00 0B ; ................
          00000170h: 00 0C 00 01 00 09 00 00 00 25 00 02 00 01 00 00 ; .........%......
          00000180h: 00 09 B2 00 02 12 03 B6 00 04 B1 00 00 00 01 00 ; ..?...?.?....
          00000190h: 0A 00 00 00 0A 00 02 00 00 00 03 00 08 00 04 00 ; ................
          000001a0h: 01 00 0D 00 00 00 02 00 0E                      ; .........

          ?

          ?

          找到第18號(hào)常量池,它是一個(gè)constant_utf8類型,在第?000000a0h 行 ?bytes=0X 68 65 6C 6C 6F 20 77 6F 72 6C 64表示的正好是我們要輸出的內(nèi)容,“hello world”,其中0X6F 表示 0,現(xiàn)在我們?cè)?X6F 之前增加4個(gè)字節(jié)的 0x6F ,如下:

          ?

          00000000h: CA FE BA BE 00 00 00 2E 00 1D 0A 00 06 00 0F 09 ; 漱壕............
          00000010h: 00 10 00 11 08 00 12 0A 00 13 00 14 07 00 15 07 ; ................
          00000020h: 00 16 01 00 06 3C 69 6E 69 74 3E 01 00 03 28 29 ; .....<init>...()
          00000030h: 56 01 00 04 43 6F 64 65 01 00 0F 4C 69 6E 65 4E ; V...Code...LineN
          00000040h: 75 6D 62 65 72 54 61 62 6C 65 01 00 04 6D 61 69 ; umberTable...mai
          00000050h: 6E 01 00 16 28 5B 4C 6A 61 76 61 2F 6C 61 6E 67 ; n...([Ljava/lang
          00000060h: 2F 53 74 72 69 6E 67 3B 29 56 01 00 0A 53 6F 75 ; /String;)V...Sou
          00000070h: 72 63 65 46 69 6C 65 01 00 0F 48 65 6C 6C 6F 57 ; rceFile...HelloW
          00000080h: 6F 72 6C 64 2E 6A 61 76 61 0C 00 07 00 08 07 00 ; orld.java.......
          00000090h: 17 0C 00 18 00 19 01 00 0B 68 65 6C 6C 6F 20 77 ; .........hello w
          000000a0h: 6F 6F 6F 6F 6F 72 6C 64 07 00 1A 0C 00 1B 00 1C ; ooooorld........
          000000b0h: 01 00 0A 48 65 6C 6C 6F 57 6F 72 6C 64 01 00 10 ; ...HelloWorld...
          000000c0h: 6A 61 76 61 2F 6C 61 6E 67 2F 4F 62 6A 65 63 74 ; java/lang/Object
          000000d0h: 01 00 10 6A 61 76 61 2F 6C 61 6E 67 2F 53 79 73 ; ...java/lang/Sys
          000000e0h: 74 65 6D 01 00 03 6F 75 74 01 00 15 4C 6A 61 76 ; tem...out...Ljav
          000000f0h: 61 2F 69 6F 2F 50 72 69 6E 74 53 74 72 65 61 6D ; a/io/PrintStream
          00000100h: 3B 01 00 13 6A 61 76 61 2F 69 6F 2F 50 72 69 6E ; ;...java/io/Prin
          00000110h: 74 53 74 72 65 61 6D 01 00 07 70 72 69 6E 74 6C ; tStream...printl
          00000120h: 6E 01 00 15 28 4C 6A 61 76 61 2F 6C 61 6E 67 2F ; n...(Ljava/lang/
          00000130h: 53 74 72 69 6E 67 3B 29 56 00 21 00 05 00 06 00 ; String;)V.!.....
          00000140h: 00 00 00 00 02 00 01 00 07 00 08 00 01 00 09 00 ; ................
          00000150h: 00 00 1D 00 01 00 01 00 00 00 05 2A B7 00 01 B1 ; ...........*?.?
          00000160h: 00 00 00 01 00 0A 00 00 00 06 00 01 00 00 00 01 ; ................
          00000170h: 00 09 00 0B 00 0C 00 01 00 09 00 00 00 25 00 02 ; .............%..
          00000180h: 00 01 00 00 00 09 B2 00 02 12 03 B6 00 04 B1 00 ; ......?...?.?
          00000190h: 00 00 01 00 0A 00 00 00 0A 00 02 00 00 00 03 00 ; ................
          000001a0h: 08 00 04 00 01 00 0D 00 00 00 02 00 0E          ; .............

          ?

          其他不改變,運(yùn)行如下:

          ?

          ?



          可以看到錯(cuò)誤提醒tag 111 非法,為什么呢,回顧前面的知識(shí),看第18號(hào)常量池:

          ?

          第18個(gè)常量:tag=0X 01,為一個(gè)constant_UTF8類型(utf8編碼的字符串),根據(jù)它的定義后面的長(zhǎng)度可變,length=0X00 0B表示后面有11個(gè)字節(jié)屬于它的內(nèi)容:bytes=0X 68 65 6C 6C 6F 20 77 6F 6f 6f 6f ? ?,再往下為另外一個(gè)常量,tag=0X6F =111,而class 文件只定義了 tag=1,3,4...11,12.。11種類型(沒(méi)有2),所以會(huì)找不到tag=111,那怎么樣才能想程序中多輸出字符呢,其實(shí)很簡(jiǎn)單,只是需要將第18號(hào)常量的長(zhǎng)度增加4個(gè),由0X0B ---》0X0F 。即如下:主要看 ?000000a0h 行 和 00000070h 行

          ?

          00000000h: CA FE BA BE 00 00 00 2E 00 1D 0A 00 06 00 0F 09 ; 漱壕............
          00000010h: 00 10 00 11 08 00 12 0A 00 13 00 14 07 00 15 07 ; ................
          00000020h: 00 16 01 00 06 3C 69 6E 69 74 3E 01 00 03 28 29 ; .....<init>...()
          00000030h: 56 01 00 04 43 6F 64 65 01 00 0F 4C 69 6E 65 4E ; V...Code...LineN
          00000040h: 75 6D 62 65 72 54 61 62 6C 65 01 00 04 6D 61 69 ; umberTable...mai
          00000050h: 6E 01 00 16 28 5B 4C 6A 61 76 61 2F 6C 61 6E 67 ; n...([Ljava/lang
          00000060h: 2F 53 74 72 69 6E 67 3B 29 56 01 00 0A 53 6F 75 ; /String;)V...Sou
          00000070h: 72 63 65 46 69 6C 65 01 00 0F 48 65 6C 6C 6F 57 ; rceFile...HelloW
          00000080h: 6F 72 6C 64 2E 6A 61 76 61 0C 00 07 00 08 07 00 ; orld.java.......
          00000090h: 17 0C 00 18 00 19 01 00 0F 68 65 6C 6C 6F 20 77 ; .........hello w
          000000a0h: 6F 6F 6F 6F 6F 72 6C 64 07 00 1A 0C 00 1B 00 1C ; ooooorld........
          000000b0h: 01 00 0A 48 65 6C 6C 6F 57 6F 72 6C 64 01 00 10 ; ...HelloWorld...
          000000c0h: 6A 61 76 61 2F 6C 61 6E 67 2F 4F 62 6A 65 63 74 ; java/lang/Object
          000000d0h: 01 00 10 6A 61 76 61 2F 6C 61 6E 67 2F 53 79 73 ; ...java/lang/Sys
          000000e0h: 74 65 6D 01 00 03 6F 75 74 01 00 15 4C 6A 61 76 ; tem...out...Ljav
          000000f0h: 61 2F 69 6F 2F 50 72 69 6E 74 53 74 72 65 61 6D ; a/io/PrintStream
          00000100h: 3B 01 00 13 6A 61 76 61 2F 69 6F 2F 50 72 69 6E ; ;...java/io/Prin
          00000110h: 74 53 74 72 65 61 6D 01 00 07 70 72 69 6E 74 6C ; tStream...printl
          00000120h: 6E 01 00 15 28 4C 6A 61 76 61 2F 6C 61 6E 67 2F ; n...(Ljava/lang/
          00000130h: 53 74 72 69 6E 67 3B 29 56 00 21 00 05 00 06 00 ; String;)V.!.....
          00000140h: 00 00 00 00 02 00 01 00 07 00 08 00 01 00 09 00 ; ................
          00000150h: 00 00 1D 00 01 00 01 00 00 00 05 2A B7 00 01 B1 ; ...........*?.?
          00000160h: 00 00 00 01 00 0A 00 00 00 06 00 01 00 00 00 01 ; ................
          00000170h: 00 09 00 0B 00 0C 00 01 00 09 00 00 00 25 00 02 ; .............%..
          00000180h: 00 01 00 00 00 09 B2 00 02 12 03 B6 00 04 B1 00 ; ......?...?.?
          00000190h: 00 00 01 00 0A 00 00 00 0A 00 02 00 00 00 03 00 ; ................
          000001a0h: 08 00 04 00 01 00 0D 00 00 00 02 00 0E          ; .............
          ?

          再運(yùn)行:

          ?


          ?






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