(1)在把int或double轉(zhuǎn)換成BigDecimal時位數(shù)就會相應(yīng)的增長，為了解決這個問題，可以將double獲long型通過自寫函數(shù)round進(jìn)行四舍五入
    后，在轉(zhuǎn)換成String,然后通過new BigDecimal()轉(zhuǎn)換過來
   
    例如：fosum = new BigDecimal(String.＆#118alueOf(round(uo1sum.double＆#118alue() + uo2sum.double＆#118alue(),3)))
 
  (2)將時間轉(zhuǎn)換成字符

        java.util.Date date = new java.util.Date(databean.getTyrq().getTime());
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
        tyrq = sdf.format(date);

  (3)將字符串轉(zhuǎn)換成時間Timestamp類型
       public  java.sql.Timestamp strToTimestamp(String str){
           java.sql.Timestamp sdate = null;

    if(str!=null){

      if(str.trim().length()==8){
        str = str.substring(0,4)+"-"+str.substring(4,6)+"-"+str.substring(6,8);

      }
    try{
     DateFormat df = DateFormat.getDateInstance(DateFormat.DEFAULT,java.util.Locale.CHINA);
     java.util.Date date = df.parse(str);
     sdate = new java.sql.Timestamp(date.getTime());
    }catch(Exception e){
      e.printStackTrace();
    }

}
  return sdate;
}
 
  (4)將double型進(jìn)行四舍五入
     public  double round(double v,int scale){

       if(scale<0){

           throw new IllegalArgumentException("The scale must be a positive integer or zero");

       }

       BigDecimal b = new BigDecimal(Double.toString(v));

       BigDecimal one = new BigDecimal("1");

       return b.divide(one,scale,BigDecimal.ROUND_HALF_UP).double＆#118alue();

   }
  (5)將int轉(zhuǎn)換成byte[]
     
    public byte[] InttoByteArray(int num){
       int temp = num;
       byte[] b = new byte[6];
      for(int i=b.length;i>-1;i--){
      b[i] = new Integer(temp&0xff).byte＆#118alue();
        temp = temp >> 8;
      }
     return b;
    }
 
  (6)將int轉(zhuǎn)換成byte
        int s=0;
        byte b = (byte)s;

轉(zhuǎn)自：中國大學(xué)生生活網(wǎng)