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          Spring+Hibernate+Acegi 的初次體驗

          系統,三種角色:教師,學生,管理員,我想讓他們的登陸都在一個界面下自動識別,而無需進行身份選擇,登陸后,他們將分別到各自的admin.jsp,stu.jsp,teacher.jsp
          在數據庫中的表結構如下(很多屬性略):
          id--- user---password--type---about

          type是用來存儲用戶的類別,分別有a,t,s分別對應三種角色
          about對應的是acegi里所需要的enable,用戶是否可用

          在model里,我們采用了繼承關系:

          父類user:

          代碼
          1. package?subject.model; ??
          2. ??
          3. public?abstract?class?User?extends?BaseObject ??
          4. { ??
          5. ?private?Integer?id; ??
          6. ?private?String?user; ??
          7. ?private?String?password; ??
          8. ?private?String?name; ??
          9. ?private?String?telphone; ??
          10. ??
          11. ??//set?and?get?method? ??
          12. ?//這個是用來反映用戶角色的關鍵函數,在子類實現,從而實現多態 ??
          13. ?public?abstract?String?getType();? ??
          14. } ??

          子類的實現:
          ======================

          代碼
          1. package?subject.model; ??
          2. ??
          3. import?subject.Constants; ??
          4. ??
          5. public?class?Teacher?extends?User ??
          6. { ??
          7. ?private?String?level;?????????//教師的職稱 ??
          8. ??
          9. //set?and?get?method ??
          10. ??
          11. ?public?String?getType() ??
          12. ?{ ??
          13. ??return?Constants.TEACHER; ??
          14. ?} ??
          15. } ??

          ================
          代碼
          1. package?subject.model; ??
          2. ??
          3. import?subject.Constants; ??
          4. ??
          5. public?class?Student?extends?User ??
          6. { ??
          7. ?private?static?final?long?serialVersionUID?=?1L; ??
          8. ??
          9. ?private?SchoolClass?schoolClass;?????????//學生的班級 ??
          10. ?private?String?sn;?????????????//學生的學號 ??
          11. ??
          12. //set?and?get?method ??
          13. ? ??
          14. ?public?String?getType() ??
          15. ?{ ??
          16. ??return?Constants.STUDENT; ??
          17. ?} ??
          18. } ??

          =================
          代碼
          1. package?subject.model; ??
          2. ??
          3. import?subject.Constants; ??
          4. ??
          5. public?class?Admin?extends?User ??
          6. { ??
          7. ?private?String?grade;???????????//管理員的級別 ??
          8. //set?and?get?method ??
          9. ??
          10. ?public?String?getType() ??
          11. ?{ ??
          12. ??return?Constants.ADMIN; ??
          13. ?} ??
          14. } ??

          對于三者所共有的屬性在數據庫里,都存在一個字段,而依據不同的角色擁有不同的含義,學生的班級則存放在了about里,只要學生有班級,他就able,否則就enable了!而管理員和教師則默認為1!

          這種是屬于一個繼承樹存放在一個表的情況,Hibernate的配置如下:

          代碼
          1. <hibernate-mapping>??
          2. ??
          3. ?<class?name="subject.model.User"?discriminator-value="not?null">??
          4. ??
          5. ??<id?name="id">??
          6. ???<generator?class="increment"?/>??
          7. ??</id>??
          8. ?? ??
          9. ??<discriminator?column="type"?type="character"?/>??
          10. ?? ??
          11. ??<property?name="user"?/>??
          12. ??<property?name="password"?/>??
          13. ??<property?name="name"?/>??
          14. ??<property?name="telphone"?/>??
          15. ??
          16. ??<subclass?name="subject.model.Admin"?discriminator-value="a">??
          17. ???<property?name="grade"?column="sn"?/>??
          18. ??</subclass>??
          19. ?? ??
          20. ??<subclass?name="subject.model.Teacher"?discriminator-value="t">??
          21. ???<property?name="level"?column="sn"?/>??
          22. ??</subclass>??
          23. ?? ??
          24. ??<subclass?name="subject.model.Student"?discriminator-value="s">??
          25. ??? ??
          26. ???<property?name="sn"?/>??
          27. ??? ??
          28. ???<many-to-one?name="schoolClass"?class="subject.model.SchoolClass"? ??
          29. ????column="about"?update="false"?insert="false"?/>??
          30. ???? ??
          31. ??</subclass>??
          32. ??
          33. ?</class>??
          34. ??
          35. </hibernate-mapping>??

          =============================================
          上面的這些都是模型的基礎,下面再講怎么樣配合Spring和Acegi實現系統的安全與登陸
          在Spring中Hibernate的配置只介紹不說明:

          代碼
          1. <!--?定義DBCP數據源?-->??
          2. ?<bean?id="dataSource"?class="org.apache.commons.dbcp.BasicDataSource"?destroy-method="close">??
          3. ??<property?name="driverClassName"?value="com.mysql.jdbc.Driver"?/>??
          4. ??<property?name="url"?value="jdbc:mysql://localhost/subject?useUnicode=true&characterEncoding=gbk"?/>??
          5. ??<property?name="username"?value="root"?/>??
          6. ??<property?name="password"?value=""?/>??
          7. ??<property?name="maxActive"?value="100"?/>??
          8. ??<property?name="maxIdle"?value="30"?/>??
          9. ??<property?name="maxWait"?value="1000"?/>??
          10. ??<property?name="defaultAutoCommit"?value="true"?/>??
          11. ??<property?name="removeAbandoned"?value="true"?/>??
          12. ??<property?name="removeAbandonedTimeout"?value="60"?/>??
          13. ?</bean>??
          14. ??
          15. ?<!--?Hibernate?-->??
          16. ?<bean?id="sessionFactory"?class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">??
          17. ??<property?name="dataSource"?ref="dataSource"?/>??
          18. ??<property?name="mappingResources">??
          19. ???<list>??
          20. ????<value>subject/model/User.hbm.xml</value>??
          21. ???</list>??
          22. ??</property>??
          23. ??<property?name="hibernateProperties">??
          24. ???<props>??
          25. ????<prop?key="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</prop>??
          26. ???</props>??
          27. ??</property>??
          28. ?</bean>??
          29. ??
          30. ?<bean?id="transactionManager"?class="org.springframework.orm.hibernate3.HibernateTransactionManager">??
          31. ??<property?name="sessionFactory"?ref="sessionFactory"?/>??
          32. ?</bean>??
          33. ??
          34. <!--?Dao對象?-->??
          35. <bean?id="userDao"?class="subject.dao.hibernate.UserDaoImpl">??
          36. ??<property?name="sessionFactory"?ref="sessionFactory"?/>??
          37. ?</bean>??
          38. ??
          39. <!--?業務邏輯?-->??
          40. ?<bean?id="txProxyTemplate"?abstract="true"?class="org.springframework.transaction.interceptor.TransactionProxyFactoryBean">??
          41. ??<property?name="transactionManager"?ref="transactionManager"?/>??
          42. ??<property?name="transactionAttributes">??
          43. ???<props>??
          44. ????<prop?key="save*">PROPAGATION_REQUIRED</prop>??
          45. ????<prop?key="remove*">PROPAGATION_REQUIRED</prop>??
          46. ????<prop?key="get*">PROPAGATION_REQUIRED,readOnly</prop>??
          47. ???</props>??
          48. ??</property>??
          49. ?</bean>??
          50. ??
          51. <bean?id="userManager"?parent="txProxyTemplate">??
          52. ??<property?name="target">??
          53. ???<bean?class="subject.service.impl.UserManagerImpl">??
          54. ????<property?name="userDao"?ref="userDao"?/>??
          55. ???</bean>??
          56. ??</property>??
          57. ?</bean>??
          58. ??
          59. <!--?Struts?-->??
          60. ?<bean?name="/user"?class="subject.web.action.UserAction"?singleton="false">??
          61. ??<property?name="userManager">??
          62. ???<ref?bean="userManager"?/>??
          63. ??</property>??
          64. ?</bean>??

          ==================
          上面具體的不用了解,無非就是調用和數據庫的操作,
          下面就要對Acegi進行聲明了:
          我不用Ctrl+c和Ctrl+V的方式對Acegi進行介紹,沒有意義,隨便google就一大堆
          我們想主要在這樣的系統中需要的安全策略都有哪些?
          1.用戶的登陸
          2.防止多個用戶登陸一個帳號
          3.用戶的注銷
          4.防止非法用戶的訪問

          我這個程序所涉及到的只有這些,下面就進行說明:

          在web.xml的聲明:

          代碼
          1. <!--?Acegi安全控制?Filter?配置?-->??
          2. ????<filter>??
          3. ????????<filter-name>securityFilter</filter-name>??
          4. ????????<filter-class>org.acegisecurity.util.FilterToBeanProxy</filter-class>??
          5. ????????<init-param>??
          6. ????????????<param-name>targetClass</param-name>??
          7. ????????????<param-value>org.acegisecurity.util.FilterChainProxy</param-value>??
          8. ????????</init-param>??
          9. ????</filter>??
          10. ???? ??
          11. ????<filter-mapping>??
          12. ????????<filter-name>securityFilter</filter-name>??
          13. ????????<url-pattern>/*</url-pattern>??
          14. ????</filter-mapping>??

          Acegi通過實現了Filter接口的FilterToBeanProxy提供一種特殊的使用Servlet Filter的方式,它委托Spring中的Bean -- FilterChainProxy來完成過濾功能,這樣就簡化了web.xml的配置,并且利用Spring IOC的優勢。FilterChainProxy包含了處理認證過程的filter列表,每個filter都有各自的功能。

          代碼
          1. <!--?========================?FILTER?CHAIN?=======================?-->??
          2. ?<bean?id="filterChainProxy"?class="org.acegisecurity.util.FilterChainProxy">??
          3. ??<property?name="filterInvocationDefinitionSource">??
          4. ???<value>??
          5. ????CONVERT_URL_TO_LOWERCASE_BEFORE_COMPARISON? ??
          6. ????PATTERN_TYPE_APACHE_ANT ??
          7. ???? ??
          8. ????/**=httpSessionContextIntegrationFilter,logoutFilter,authenticationProcessingFilter, ??
          9. ?????????securityContextHolderAwareRequestFilter,exceptionTranslationFilter,filterInvocationInterceptor ??
          10. ???</value>??
          11. ??</property>??
          12. ?</bean>??

          大體上先介紹一下:
          httpSessionContextIntegrationFilter:每次request前 HttpSessionContextIntegrationFilter從Session中獲取Authentication對象,在request完后, 又把Authentication對象保存到Session中供下次request使用,此filter必須其他Acegi filter前使用,使之能跨越多個請求。
          logoutFilter:用戶的注銷
          authenticationProcessingFilter:處理登陸請求
          exceptionTranslationFilter:異常轉換過濾器
          filterInvocationInterceptor:在訪問前進行權限檢查

          這些就猶如在web.xml聲明一系列的過濾器,不過當把他們都聲明在spring中就可以享受Spring給我們帶來的方便了。

          下面就是對這些過濾器的具體聲明:
          只對有用的地方進行聲明,別的地方幾乎都是默許的

          代碼
          1. <!--?========================?FILTER?=======================?-->??
          2. ?<bean?id="httpSessionContextIntegrationFilter"? ??
          3. ??class="org.acegisecurity.context.HttpSessionContextIntegrationFilter"?/>??
          4. ??
          5. ?<bean?id="logoutFilter"?class="org.acegisecurity.ui.logout.LogoutFilter">??
          6. ??<constructor-arg?value="/index.htm"?/>?????????????離開后所轉向的位置 ??
          7. ??<constructor-arg>??
          8. ????????????<list>??
          9. ????????????????<bean?class="org.acegisecurity.ui.logout.SecurityContextLogoutHandler"/>??
          10. ????????????</list>??
          11. ????????</constructor-arg>??
          12. ??<property?name="filterProcessesUrl"?value="/logout.htm"?/>????????定義用戶注銷的地址, ??
          13. ?</bean>??
          14. ??

          下面的這個過濾器,我們根據自己的需求有了自己的實現:
          代碼
          1. ?<bean?id="authenticationProcessingFilter"?class="subject.web.filter.UserAuthenticationProcessingFilter">??
          2. ??<property?name="authenticationManager"?ref="authenticationManager"/>??下面會介紹的用來起到認證管理的作用 ??
          3. ??<property?name="authenticationFailureUrl"?value="/login.htm?error=wrong"/>??登陸失敗的地址 ??
          4. ??<property?name="defaultTargetUrl"?value="/login.htm"/>???????登陸成功的地址 ??
          5. ??<property?name="filterProcessesUrl"?value="/j_security_check"/>??????登陸請求的地址 ??
          6. ??<property?name="userManager"?ref="userManager"/>????????自己添加的屬性,這樣就可以訪問到我們的業務邏輯 ??
          7. ??<property?name="exceptionMappings">???出現異常所對應的地址 ??
          8. ????????????<value>??
          9. ????????????????org.acegisecurity.AuthenticationException=/login.htm?error=fail?????登陸失敗????????????????org.acegisecurity.concurrent.ConcurrentLoginException=/login.htm?error=too????????已登陸了 ??
          10. ????????????</value>??
          11. ????????</property>??
          12. ?</bean>??
          13. ? ??
          14. ?<bean?id="securityContextHolderAwareRequestFilter"?class="org.acegisecurity.wrapper.SecurityContextHolderAwareRequestFilter"/>??
          15. ??
          16. ?<bean?id="exceptionTranslationFilter"?class="org.acegisecurity.ui.ExceptionTranslationFilter">??
          17. ??<property?name="authenticationEntryPoint">??
          18. ???<bean?class="org.acegisecurity.ui.webapp.AuthenticationProcessingFilterEntryPoint">??
          19. ????<property?name="loginFormUrl"?value="/login.htm?error=please"/>//如果用戶沒登陸就想訪問,先到這里登陸吧 ??
          20. ????<property?name="forceHttps"?value="false"/>??
          21. ???</bean>??
          22. ??</property>??
          23. ?</bean>??
          24. ? ??
          25. ?<bean?id="filterInvocationInterceptor"?class="org.acegisecurity.intercept.web.FilterSecurityInterceptor">??
          26. ??<property?name="authenticationManager"?ref="authenticationManager"/>???????認證服務 ??
          27. ??<property?name="accessDecisionManager">??
          28. ???<bean?class="org.acegisecurity.vote.AffirmativeBased">??
          29. ????<property?name="allowIfAllAbstainDecisions"?value="false"/>??
          30. ????<property?name="decisionVoters">??
          31. ?????<list>??
          32. ??????<bean?class="org.acegisecurity.vote.RoleVoter">??
          33. ????????????????????<property?name="rolePrefix"?value=""/>?????????//這里定義數據庫中存放的角色和我們在這里聲明的角色間是否需要加個前綴?我沒加 ??
          34. ????????????????</bean>??
          35. ?????</list>??
          36. ????</property>??
          37. ???</bean>??
          38. ??</property>??
          39. ??<property?name="objectDefinitionSource">??
          40. ????????????<value>??
          41. ????????????????PATTERN_TYPE_APACHE_ANT ??
          42. ???????????????? ??
          43. ????????????????/admin.htm*=a?????????這里就是數據庫中對應的tyep?a ??
          44. ????????????????/student*=s???????????由于沒有前綴和數據庫里一樣 ??
          45. ????????????????/teacher*=t ??
          46. ????????????</value>??
          47. ????????</property>??
          48. ?</bean>??
          49. ? ??
          50. ?<bean?id="loggerListener"??
          51. ??????????class="org.acegisecurity.event.authentication.LoggerListener"/>???????記錄事件 ??
          52. ??
          53. 下面就要說明我們的認證服務了,其起到的關鍵作用就是用來保證用戶登陸身份的驗證: ??
          54. ??
          55. 它將驗證的功能委托給多個Provider,并通過遍歷Providers,?以保證獲取不同來源的身份認證,若某個Provider能成功確認當前用戶的身份,authenticate()方法會返回一個完整的包含用戶授權信息的Authentication對象,否則會拋出一個AuthenticationException。 ??
          56. ??
          57. 先聲明一個管理器吧,在上面的過濾器中都已經用到過了 ??
          58. <!--?========================?AUTHENTICATION?=======================?-->??
          59. ?<bean?id="authenticationManager"?class="org.acegisecurity.providers.ProviderManager">??
          60. ??<property?name="providers">??
          61. ???<list>??
          62. ????<ref?local="daoAuthenticationProvider"?/>???我僅僅用到?從數據庫中讀取用戶信息驗證身份 ??
          63. ???</list>??
          64. ??</property>??
          65. ??<property?name="sessionController">??
          66. ???<bean?id="concurrentSessionController"? ??
          67. ????class="org.acegisecurity.concurrent.ConcurrentSessionControllerImpl">??
          68. ????<property?name="maximumSessions">??
          69. ?????<value>1</value>每個用戶同時登陸一位 ??
          70. ????</property>??
          71. ????<property?name="sessionRegistry">??
          72. ?????<bean?id="sessionRegistry"?class="org.acegisecurity.concurrent.SessionRegistryImpl"?/>??
          73. ????</property>??
          74. ????<property?name="exceptionIfMaximumExceeded"?value="true"?/>??
          75. ???</bean>??
          76. ??</property>??
          77. ?</bean>??
          78. ?來實現唯一的一個Provider,從數據庫驗證身份 ??
          79. ?<bean?id="daoAuthenticationProvider"?class="org.acegisecurity.providers.dao.DaoAuthenticationProvider">??
          80. ??<property?name="userDetailsService">??
          81. ???<bean?id="jdbcDaoImpl"??
          82. ????????????class="org.acegisecurity.userdetails.jdbc.JdbcDaoImpl">??
          83. ??????????<property?name="dataSource"?ref="dataSource"/>??
          84. ??????????<property?name="usersByUsernameQuery">??
          85. ??????????????<value>??
          86. ??????????????????select?user,password,about?from?user?where?user?=??????????查找用戶的查詢語句,只需要把你數據庫中的用戶和密碼以及enable相對應上就行 ??
          87. ??????????????</value>??
          88. ??????????</property>??
          89. ??????????<property?name="authoritiesByUsernameQuery">??
          90. ??????????????<value>??
          91. ??????????????????select?user,type?from?user?where?user?=?????????????這里就是把用戶和權限對應上,在appfuse中用的兩個表,我都放一個表里了,所以就用這一個就行問題的關鍵是要讓它能找到兩個字段,構成一個對象 ??
          92. ??????????????</value>??
          93. ??????????</property>??
          94. ??????</bean>??
          95. ??</property>??
          96. ??<property?name="userCache">?緩存都這么寫: ??
          97. ???<bean?class="org.acegisecurity.providers.dao.cache.EhCacheBasedUserCache">??
          98. ????<property?name="cache">??
          99. ?????<bean?class="org.springframework.cache.ehcache.EhCacheFactoryBean">??
          100. ??????<property?name="cacheManager">??
          101. ???????<bean?class="org.springframework.cache.ehcache.EhCacheManagerFactoryBean"/>??
          102. ??????</property>??
          103. ??????<property?name="cacheName"?value="userCache"/>??
          104. ?????</bean>??
          105. ????</property>??
          106. ???</bean>??
          107. ??</property>??
          108. ?</bean>??

          ==============
          對于上面登陸請求的處理器我借鑒了springSide,實現的方法如下:
          代碼
          1. package?subject.web.filter; ??
          2. ??
          3. import?javax.servlet.http.HttpServletRequest; ??
          4. import?javax.servlet.http.HttpServletResponse; ??
          5. import?javax.servlet.http.HttpSession; ??
          6. ??
          7. import?org.acegisecurity.Authentication; ??
          8. import?org.acegisecurity.context.SecurityContext; ??
          9. import?org.acegisecurity.context.SecurityContextHolder; ??
          10. import?org.acegisecurity.ui.webapp.AuthenticationProcessingFilter; ??
          11. import?org.acegisecurity.userdetails.UserDetails; ??
          12. ??
          13. import?subject.Constants; ??
          14. import?subject.model.User; ??
          15. import?subject.service.UserManager; ??
          16. ??
          17. public?class?UserAuthenticationProcessingFilter?extends??
          18. ??AuthenticationProcessingFilter ??
          19. { ??
          20. ?private?UserManager?userManager; ??
          21. ??
          22. ?public?void?setUserManager(?UserManager?userManager?) ??
          23. ?{ ??
          24. ??this.userManager?=?userManager; ??
          25. ?} ??
          26. ??
          27. ?protected?boolean?requiresAuthentication(?HttpServletRequest?request?, ??
          28. ???HttpServletResponse?response?) ??
          29. ?{ ??
          30. ??boolean?requiresAuth?=?super.requiresAuthentication(?request,?response?); ??
          31. ??HttpSession?httpSession?=?null; ??
          32. ??try??
          33. ??{ ??
          34. ???httpSession?=?request.getSession(?false?); ??
          35. ??} ??
          36. ??catch?(?IllegalStateException?ignored?) ??
          37. ??{ ??
          38. ??} ??
          39. ??if?(?httpSession?!=?null?) ??
          40. ??{ ??
          41. ???if?(?httpSession.getAttribute(?Constants.USER?)?==?null?) ??
          42. ???{ ??
          43. ????if?(?!requiresAuth?) ??
          44. ????{ ??
          45. ?????SecurityContext?sc?=?SecurityContextHolder.getContext(); ??
          46. ?????Authentication?auth?=?sc.getAuthentication(); ??
          47. ?????if?(?auth?!=?null??
          48. ???????&&?auth.getPrincipal()?instanceof?UserDetails?) ??
          49. ?????{ ??
          50. ??????UserDetails?ud?=?(UserDetails)?auth.getPrincipal();//上面聲明的sql無非就是要包裝成這個對象 ??
          51. ??????User?user?=?userManager.getUser(?ud.getUsername()?);從業務邏輯里找到用戶,放到session里 ??
          52. ??????httpSession.setAttribute(?Constants.USER,?user?); ??
          53. ?????} ??
          54. ????} ??
          55. ???} ??
          56. ??} ??
          57. ??return?requiresAuth; ??
          58. ?} ??
          59. } ??

          在看看我的login.htm在登陸成功時是怎么工作的吧?

          代碼
          1. public?class?UserAction?extends?BaseAction ??
          2. { ??
          3. ?private?UserManager?mgr; ??
          4. ??
          5. ?public?void?setUserManager(?UserManager?mgr?) ??
          6. ?{ ??
          7. ??this.mgr?=?mgr; ??
          8. ?} ??
          9. ??
          10. ?public?ActionForward?login(?ActionMapping?mapping?,?ActionForm?form?, ??
          11. ???HttpServletRequest?request?,?HttpServletResponse?response?) ??
          12. ???throws?Exception ??
          13. ?{ ??
          14. ??User?user?=?(User)?getSessionObject(?request,?Constants.USER?); ??
          15. ??ActionMessages?msg?=?new?ActionMessages(); ??
          16. ??if?(?user?!=?null?) ??
          17. ??{ ??
          18. ???return?new?ActionForward(??user.getType()?+?".htm",?true?);成功就去type.htm ??
          19. ??} ??
          20. ??else??
          21. ??{ ??
          22. ???String?error?=?getParameter(?request,?Constants.ERROR?); ??
          23. ???if?(?error?!=?null?)對于不同的錯誤,都加以提示 ??
          24. ???{ ??
          25. ????if?(?error.equalsIgnoreCase(?"wrong"?)?) ??
          26. ?????msg.add(?"msg",?new?ActionMessage(?"fail.login.wrong"?)?); ??
          27. ????else?if?(?error.equalsIgnoreCase(?"too"?)?) ??
          28. ?????msg.add(?"msg",?new?ActionMessage(?"fail.login.too"?)?); ??
          29. ????else?if?(?error.equalsIgnoreCase(?"fail"?)?) ??
          30. ?????msg.add(?"msg",?new?ActionMessage(?"fail.login.fail"?)?); ??
          31. ????else??
          32. ?????msg.add(?"msg",?new?ActionMessage(?"fail.login.please"?)?); ??
          33. ???} ??
          34. ???else??
          35. ????msg.add(?"msg",?new?ActionMessage(?"fail.login.please"?)?); ??
          36. ??} ??
          37. ??saveErrors(?request,?msg?); ??
          38. ??return?mapping.findForward(?"fail"?); ??
          39. ?} ??
          40. ??
          41. } ??

          當然,Acegi需要介紹的東西太多了,我只把我這次認為有必要解釋的東西寫在了上面讓大家來參考,作為能google到的東西,比如對于認證的方式還有很多,我就沒有詳細的介紹,在學習Acegi過程中,把它自帶的例子弄清楚很關鍵,希望大家一起學習一起共勉!

          posted on 2007-03-13 17:19 鴻雁 閱讀(313) 評論(0)  編輯  收藏

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