這個(gè)東西比較有趣，代碼還要區(qū)分是否在Eclipse環(huán)境下運(yùn)行。
先看看現(xiàn)象，以EMF例子Library.ecore為例, 測(cè)試代碼如下：
public?class?Test?{
????public?static?void?main(String[]?args)?throws?IOException?{
????????ResourceSet?rs?=?new?ResourceSetImpl();
????????rs.getResourceFactoryRegistry().getExtensionToFactoryMap().put(
????????????????Resource.Factory.Registry.DEFAULT_EXTENSION,
????????????????new?XMIResourceFactoryImpl()); //outside eclipse
????????Resource?resource?=?rs.createResource(URI
????????????????.createURI(EXTLibraryPackage.eNS_URI));
????????//step?a
????????Library?library?=?EXTLibraryFactory.eINSTANCE.createLibrary();
????????library.setName("some?lib");
????????resource.getContents().add(library);
????????//step?b
//????????Book?book?=?EXTLibraryFactory.eINSTANCE.createBook();
//????????book.setTitle("some?book");
//????????Employee?employee?=?EXTLibraryFactory.eINSTANCE.createEmployee();
//????????employee.setFirstName("some?one");
????????//step?c
//????????library.getBooks().add(book);
//????????library.getEmployees().add(employee);
????????//step?d
//????????resource.getContents().add(book);
????
//????????System.out.println(EcoreUtil.getURI(employee));
//????????System.out.println(EcoreUtil.getURI(book));
????????resource.save(System.out,?null);
????}
}

步驟 輸出
a ----------------
<?xml version="1.0" encoding="ASCII"?>
<extlib:Library xmi:version="2.0" xmlns:xmi="http:///org/eclipse/emf/examples/library/extlibrary.ecore/1.0.0" name="some lib"/>
b?#//
#//
<?xml version="1.0" encoding="ASCII"?>
<extlib:Library xmi:version="2.0" xmlns:xmi="http:///org/eclipse/emf/examples/library/extlibrary.ecore/1.0.0" name="some lib"/>
c http:///org/eclipse/emf/examples/library/extlibrary.ecore/1.0.0#//@employees.0
#//
<?xml version="1.0" encoding="ASCII"?>
<extlib:Library xmi:version="2.0" xmlns:xmi="http:///org/eclipse/emf/examples/library/extlibrary.ecore/1.0.0" name="some lib">
? <employees firstName="some one"/>
</extlib:Library>
d http:///org/eclipse/emf/examples/library/extlibrary.ecore/1.0.0#/0/@employees.0
http:///org/eclipse/emf/examples/library/extlibrary.ecore/1.0.0#/1
<?xml version="1.0" encoding="ASCII"?>
<xmi:XMI xmi:version="2.0" xmlns:xmi="http:///org/eclipse/emf/examples/library/extlibrary.ecore/1.0.0">
? <extlib:Library name="some lib">
??? <employees firstName="some one"/>
? </extlib:Library>
? <extlib:Book title="some book"/>
</xmi:XMI>

可以看到，沒有加入lib的時(shí)候，employee/book實(shí)例的URI都是#//, employee加入以后有了#//@employees.0, book依舊。
在book加入resource以后有了#/1的URI, employee/book在containment定義分別是true,false，所以employee加入lib以后就隨lib加入resource（實(shí)例容器）。book則要單獨(dú)加入。

另外一個(gè)有趣的現(xiàn)象是Resource可以容納多個(gè)實(shí)例，在step d可以看到輸出的根節(jié)點(diǎn)由lib變成匿名容器。

如果lib不加入resource又如何呢？
步驟 輸出
a ----------------
b?#//
#//
c #///@employees.0
#//
d ----------------
沒加入resource之前，URI是未知的，知道的只是相對(duì)父節(jié)點(diǎn)的相對(duì)segment.