選擇java 進(jìn)入自由開放的國(guó)度

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          數(shù)據(jù)加載中……

          C++猜數(shù)字游戲

          /*-----------------------------------------------------------
            猜數(shù)字游戲
            C++中數(shù)組的運(yùn)用,條件語句,賦值語句,循環(huán)語句等元素的應(yīng)用
          -----------------------------------------------------------*/

          #include <iostream>
          #include <string>

          using namespace std;

          const int seq_size = 18;
          const int max_seq  = 6;
          const int max_tries = 3;  

          string seq_names[max_seq] = {
            "Fibonacci",
            "Lucas",
            "Pell",
            "Triangular",
            "Square",
            "Pentagonal"
          };

          int elem_seq[ seq_size ] = {
             1, 2, 3,   //Fibonacci
             3, 4, 7,   //lucas
             2, 5, 12,  //Pell
             3, 6, 10,  //Triangular
             4, 9, 16,  //Square
             5, 12, 22  //Pentagonal
          };

          int usr_val;          //the value user inputed
          int num_total;        //total times
          int num_tries = 0;    //the try number
          int num_rights = 0;    //the right times
          int cur_tuple = 0;    //the location pointer of current array

          double usr_score;     //user's score
          char usr_rsp;        //try again?


          bool go_for_it = true; //try again
          bool next_seq  = true; //display the next number
          bool got_it    = false;//right or error?


          int main(){
           while ( next_seq && cur_tuple < seq_size) {
             //display the array
                cout << " the First two elements of the sequence are: "
               << elem_seq[ cur_tuple ] << ", "
               << elem_seq[ cur_tuple + 1]
               << " in the "
               << seq_names[ cur_tuple/3]
               << "  sequence.\n"
               << "What is the next element?";
              
            //初始化,進(jìn)入循環(huán),判斷是否正確
            got_it    = false;
            go_for_it = true;
                  num_tries = 0;
            while ((!got_it) && (go_for_it)) {
               int usr_guess;
               cin >> usr_guess;
               num_tries++;
              
               if (usr_guess == elem_seq[ cur_tuple + 2]){
                 //答對(duì)了
              cout << "Congratulations! you are right! \n";
              got_it = true;
                 num_rights++;
               }
               else{
                 //猜錯(cuò)了
              //告訴用戶是錯(cuò)的,詢問是否愿意再試一次
                switch (num_tries){
                case 1 :
                 cout << "Oops! Nice guess but not quite it.\n";
                 break;
                case 2 :
                 cout << "Hmm, Sorry, wront a second time. \n";
                 break;
                case 3 :
                 cout << "Ah, this is harder than it looks, isn't it?\n";
                 go_for_it = false; //跳出
                 break;
                default :
                 cout << "It must be getting pretty frustrating by now! \n";
                 break;
                }//switch
                if (num_tries < 3) cout << "Do you try it again? (Y|N)" ;
                cin  >> usr_rsp;
                         if (usr_rsp == 'N' || usr_rsp == 'n')
                 go_for_it = false;
               }//if
                  }//small while
            
            cout << "Want to try another sequence? (Y/N)";
            char try_again;
            cin >> try_again;
            if (try_again == 'N' || try_again == 'n')
             next_seq = false;
            
            cur_tuple += 3;             //指到下一個(gè)數(shù)列
            num_total += num_tries;     //總數(shù)
           };//large while
           
            //輸出得分,簡(jiǎn)單統(tǒng)計(jì)信息
           cout << "---------------------------- \n"
             << "the total : " << num_total
             << "the right times: " << num_rights << "\n"
             << "---------------------------- \n";
            return 0;
          }

          posted on 2005-12-23 16:15 soochow_hhb 以java論成敗 以架構(gòu)論英雄 閱讀(809) 評(píng)論(0)  編輯  收藏


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