Rory's Blog
          Happy study,Happy work,Happy life
          posts - 22,  comments - 46,  trackbacks - 0
          xstream是個好東西。對于配置文件的讀取很方便。在mybog中我就用到了。不過今天打算用yupoo的api來做相冊。發現xstream對于xmlnode的attribute解析支持不是那么的好。
          對于這種節點格式的非常的簡單
          <result>
          ????
          <page>1</page>
          ????
          <pages>1</pages>
          ????
          <perpage>100</perpage>
          ????
          <total>19</total>
          ????
          <photos>
          ????????
          <photo>
          ????????????
          <id>ff8080810fc8ac78010fd3f158d40a52</id>
          ????????????
          <owner>ff8080810f1a387b010f1a83d6530dfc</owner>
          ????????????
          <title>Gmail-2</title>
          ????????????
          <host>4</host>
          ????????????
          <dir>20061230</dir>
          ????????????
          <filename>231905_1463411198</filename>
          ????????
          </photo>
          ????
          </photos>
          </result>

          簡單的alias一下就可以讀到值了
          File?file?=?new?File("src/test/java/com/jdkcn/test/result.xml");
          BufferedReader?reader?
          =?new?BufferedReader(new?InputStreamReader(new?FileInputStream(file),?"UTF-8"));
          XStream?stream?
          =?new?XStream();
          stream.alias(
          "result",?YupooResult.class);
          stream.alias(
          "photo",YupooPhoto.class);
          YupooResult?result?
          =?(YupooResult)stream.fromXML(reader);
          可是Yupoo的api返回的xmlrpc的結果是這樣的
          <result?page="1"?pages="1"?perpage="100"?total="19">
          ????
          <photos>
          ????????
          <photo?id="ff8080810fc8ac78010fd3f158d40a52"
          ????????????owner
          ="ff8080810f1a387b010f1a83d6530dfc"?title="Gmail-2"?host="4"
          ????????????dir
          ="20061230"?filename="231905_1463411198"?/>
          ????
          </photos>
          </result>
          這樣就load不到值了。沒法去mailist里面找答案,果然有人問。
          Hello,
          
          I am not sure about the subject but here is what I needed help for:
          
          XML:
          
          <field name="value">I am a Field.</field>
          
          I have already tried several structures and nothing seem to work.
          
          Is this possible for XStream? :)
          
          How is the Java class form to support this?
          
          Thanks!




          有人回答是看Converter的文檔。果然找到答案了。
          自己寫一個converter就可以了。
          下面是我的converter
          package?com.jdkcn.xstream;

          import?java.util.ArrayList;
          import?java.util.List;

          import?com.jdkcn.yupoo.YupooPhoto;
          import?com.jdkcn.yupoo.YupooResult;
          import?com.thoughtworks.xstream.converters.Converter;
          import?com.thoughtworks.xstream.converters.MarshallingContext;
          import?com.thoughtworks.xstream.converters.UnmarshallingContext;
          import?com.thoughtworks.xstream.io.HierarchicalStreamReader;
          import?com.thoughtworks.xstream.io.HierarchicalStreamWriter;

          /**
          ?*?
          @author?<a?href="mailto:rory.cn@gmail.com">somebody</a>
          ?*?
          @since?Jan?16,?2007?6:12:35?PM
          ?*?
          @version?$Id?YupooResultConverter.java$
          ?
          */
          public?class?YupooResultConverter?implements?Converter?{
          ????
          /*?(non-Javadoc)
          ?????*?@see?com.thoughtworks.xstream.converters.Converter#marshal(java.lang.Object,?com.thoughtworks.xstream.io.HierarchicalStreamWriter,?com.thoughtworks.xstream.converters.MarshallingContext)
          ?????
          */
          ????
          public?void?marshal(Object?obj,?HierarchicalStreamWriter?writer,?MarshallingContext?context)?{
          ????????
          //?FIXME?unfinish.
          ????}

          ????
          /*?(non-Javadoc)
          ?????*?@see?com.thoughtworks.xstream.converters.Converter#unmarshal(com.thoughtworks.xstream.io.HierarchicalStreamReader,?com.thoughtworks.xstream.converters.UnmarshallingContext)
          ?????
          */
          ????
          public?Object?unmarshal(HierarchicalStreamReader?reader,?UnmarshallingContext?context)?{
          ????????YupooResult?result?
          =?new?YupooResult();
          ????????result.setPage(
          new?Integer(reader.getAttribute("page")));
          ????????result.setPages(
          new?Integer(reader.getAttribute("pages")));
          ????????result.setPerpage(
          new?Integer(reader.getAttribute("perpage")));
          ????????result.setTotal(
          new?Integer(reader.getAttribute("total")));
          ????????reader.moveDown();
          ????????List
          <YupooPhoto>?photos?=?new?ArrayList<YupooPhoto>();
          ????????
          while(reader.hasMoreChildren())?{
          ????????????reader.moveDown();
          ????????????YupooPhoto?photo?
          =?new?YupooPhoto();
          ????????????photo.setDir(reader.getAttribute(
          "dir"));
          ????????????photo.setFilename(reader.getAttribute(
          "filename"));
          ????????????photo.setHost(reader.getAttribute(
          "host"));
          ????????????photo.setId(reader.getAttribute(
          "id"));
          ????????????photo.setOwner(reader.getAttribute(
          "owner"));
          ????????????photo.setTitle(reader.getAttribute(
          "title"));
          ????????????photos.add(photo);
          ????????????reader.moveUp();
          ????????}
          ????????result.setPhotos(photos);
          ????????
          return?result;
          ????}
          ????
          /*?(non-Javadoc)
          ?????*?@see?com.thoughtworks.xstream.converters.ConverterMatcher#canConvert(java.lang.Class)
          ?????
          */
          ????
          public?boolean?canConvert(Class?clazz)?{
          ????????
          return?clazz.equals(YupooResult.class);
          ????}
          }

          然后調用的地方修改一下就ok了。
          XStream?stream?=?new?XStream();
          stream.registerConverter(
          new?YupooResultConverter());
          stream.alias(
          "result",?YupooResult.class);



          參考:
          http://xstream.codehaus.org/converter-tutorial.html

          2007年1月18日更新。
          這里感謝網友 Ivan Chen(西濱)?的提示。原來新版的xstream可以簡單的解決了。在1.2.1的doc里面找到了這個兩個方法。

          useAttributeFor

          public void useAttributeFor(java.lang.String?fieldName,
                                      java.lang.Class?type)
          Use an XML attribute for a field or a specific type.

          Parameters:
          fieldName - the name of the field
          type - the Class of the type to be rendered as XML attribute
          Throws:
          XStream.InitializationException - if no AttributeMapper is available
          Since:
          1.2

          useAttributeFor

          public void useAttributeFor(java.lang.Class?type)
          Use an XML attribute for an arbotrary type.

          Parameters:
          type - the Class of the type to be rendered as XML attribute
          Throws:
          XStream.InitializationException - if no AttributeMapper is available
          Since:
          1.2

          這兩個方法都是從1.2開始支持的。
          也不用自己寫converter了。這樣就可以了
          ????????stream.alias("result",?YupooResult.class);
          ????????stream.useAttributeFor(
          "page",?Integer.class);
          ????????stream.useAttributeFor(
          "pages",?Integer.class);
          ????????stream.useAttributeFor(
          "perpage",?Integer.class);
          ????????stream.useAttributeFor(
          "total",?Integer.class);
          ????????stream.alias(
          "photo",?YupooPhoto.class);
          ????????stream.useAttributeFor(
          "id",?String.class);
          ????????stream.useAttributeFor(
          "owner",?String.class);
          ????????stream.useAttributeFor(
          "title",?String.class);
          ????????stream.useAttributeFor(
          "host",?String.class);
          ????????stream.useAttributeFor(
          "dir",?String.class);
          ????????stream.useAttributeFor(
          "filename",?String.class);

          創造共用協議:署名,非商業,保持一致
          ?? 除經特別注明外,本文章版權歸莫多泡泡所有.
          署名,非商業用途,保持一致.???somebody(莫多)
          posted @ 2007-01-17 18:24 莫多 閱讀(8001) | 評論 (2)編輯 收藏

          ? 上周更新了一下myblog,添加了一個Filter,做統計訪問用。可是后來發現出現亂碼問題了。找了很久都沒有找到問題。debug的時候看到 CharacterEncodingFilter確實是執行了。不過就是沒有效果。執行之前是ISO-8859-1編碼的,執行之后還是, CharacterEncodingFilter就沒有起到作用。后來終于找到問題的原因了。原來是Filter配置先后順序的原因。
          ?????? 剛開始的配置是這樣的:

          ???? < filter-mapping >
          ????????
          < filter-name > requestCounterFilter </ filter-name >
          ????????
          < url-pattern > *.jhtml </ url-pattern >
          ????
          </ filter-mapping >
          ??
          ????
          < filter-mapping >
          ????????
          < filter-name > encodingFilter </ filter-name >
          ????????
          < url-pattern > /dwr/* </ url-pattern >
          ????
          </ filter-mapping >
          ????
          ????
          < filter-mapping >
          ????????
          < filter-name > encodingFilter </ filter-name >
          ????????
          < url-pattern > *.jhtml </ url-pattern >
          ????
          </ filter-mapping >
          ????
          ????
          < filter-mapping >
          ????????
          < filter-name > encodingFilter </ filter-name >
          ????????
          < url-pattern > *.jsp </ url-pattern >
          ????
          </ filter-mapping >

          ? 先經過那個統計的filter然后再經過編碼的filter。這樣的話編碼的filter就不起作用了。只要吧編碼的filter放到最前面就沒有問題了。改成這樣就好。

          ???? < filter-mapping >
          ????????
          < filter-name > encodingFilter </ filter-name >
          ????????
          < url-pattern > /dwr/* </ url-pattern >
          ????
          </ filter-mapping >
          ????
          ????
          < filter-mapping >
          ????????
          < filter-name > encodingFilter </ filter-name >
          ????????
          < url-pattern > *.jhtml </ url-pattern >
          ????
          </ filter-mapping >
          ????
          ????
          < filter-mapping >
          ????????
          < filter-name > encodingFilter </ filter-name >
          ????????
          < url-pattern > *.jsp </ url-pattern >
          ????
          </ filter-mapping >
          ????
          ????
          < filter-mapping >
          ????????
          < filter-name > requestCounterFilter </ filter-name >
          ????????
          < url-pattern > *.jhtml </ url-pattern >
          ????
          </ filter-mapping >


          以后大家一定要注意啊。順序問題也是很重要的。
          創造共用協議:署名,非商業,保持一致?? 除經特別注明外,本文章版權歸莫多泡泡所有.
          署名,非商業用途,保持一致.???somebody(莫多)

          posted @ 2006-12-27 10:37 莫多 閱讀(2691) | 評論 (3)編輯 收藏

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