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          Java產生隨機數代碼【轉載】

          //根據不同的難度產生隨機字母和數字
          for(int i=0; readomNumStart.length()<4; i++) {
          if(difficult == 1) {

          //產生隨機的0-9的數字
          a = String.valueOf((int)(Math.random() * 10)) ;
          }
          if(difficult == 2) {

          //在0-9和a,b,c,d中隨機產生。
          String[] readomWord = {"0","1","2","3","4","5","6","7","8","9","a","b","c","d"};
          int readomWordIndex = (int)(Math.random() * 13);
          a = readomWord[readomWordIndex];
          }
          if(difficult == 3) {

          //產生隨機的字母
          char readomLetter = (char)(Math.random ()*26+'a');
          a = String.valueOf(readomLetter) ;
          }
          if(difficult == 4) {

          //產生隨機的數字和字母的組合
          String[] readomHard = new String[20];
          int readomWordIndex = (int)(Math.random() * 19);
          for(int j=0; j<20; j++) {
          int readomWordNum = (int)(Math.random() * 10);
          char readomLetter = (char)(Math.random ()*26+'a');
          if(readomWordNum % 2 == 0) {
          readomHard[j] = readomWordNum + "";
          }else{
          readomHard[j] = String.valueOf(readomLetter);
          }
          }
          a = readomHard[readomWordIndex];
          }

          //
          char[] numbersAndLetters = ("0123456789" + "abcdefghijklmnopqrstuvwxyz" + "ABCDEFGHIJKLMNOPQRSTUVWXYZ").toCharArray();
          char[] randBuffer = new char[length];
          for (int i = 0; i < randBuffer.length; i++) {
          randBuffer[i] = numbersAndLetters[randGen.nextInt(numbersAndLetters.length)];
          }
          return new String(randBuffer);


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          posted on 2009-04-08 16:11 liudecai_zan@126.com 閱讀(149) 評論(0)  編輯  收藏 所屬分類: 程序人生

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