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kohri — Wed, 25 Apr 2012 14:36:00 GMT

本来以�ؓ有了date4j��׃��事无休了�Q�结果在工作的时候发觉有不少脚步仅仅需要两三个��单的class执行一下就可以完成��d��了。也��是说即使是date4j�Q�相对于�q�两三个甚至是一个class来说�q�是�q�于臃肿了。于是乎自己写了个简单的日期��装�c�R�?br />主要功能�?
1.获取当前旉��
2.获取当前�q�_��月，日，�Ӟ��分，�U?br />3.获取指定日期的年�Q�月�Q�日�Q�时�Q�分�Q�秒
4.获取两个日期的时间差(包括�q�月日时分秒)
5.��字�W�窜�c�d��转成java.util.date�c�d��
6.指定日期��d��旉��

package com.kohri.date;

import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
import java.util.GregorianCalendar;

/**
* @descriped a simple class for date
* @author Kohri
* @date 2012/4/22
* @version 1.0
*/
public class SimpleDate {

    private static String defaultFormat = "yyyy-MM-dd HH:mm:ss";
    private static SimpleDateFormat sf = null ;
    private static Calendar cal = Calendar.getInstance();
    private static Date date = null;

    /**
     * get current date time (default 'yyyy-MM-dd HH:mm:ss')
     * @return string
     */
    public static String getDateNow() {
        sf = new SimpleDateFormat(defaultFormat);
        String currentTime = "";
        currentTime = sf.format(new Date());
        return currentTime;
    }

    /**
     * get year (default now)
     * @return int
     */
    public static int getYear(){
        int currentYear = cal.get(Calendar.YEAR);
        return currentYear;
    }

    /**
     * get mon (default now)
     * @return int
     */
    public static int getMonth(){
        int currentMonth = cal.get(Calendar.MONTH) + 1;
        return currentMonth;
    }

    /**
     * get day of month (default now)
     * @return int
     */
    public static int getDay(){
        int currentDayOfMonth = cal.get(Calendar.DAY_OF_MONTH);
        return currentDayOfMonth;
    }

    /**
     * get hours (default now)
     * @return int
     */
    public static int getHours(){
        int currentHours = cal.get(Calendar.HOUR_OF_DAY);
        return currentHours;
    }

    /**
     * get  minutes (default now)
     * @return int
     */
    public static int getMinutes(){
        int currentMinute = cal.get(Calendar.MINUTE);
        return currentMinute;
    }

    /**
     * get seconds (default now)
     * @return int
     */
    public static int getSeconds(){
        int currentSecond = cal.get(Calendar.SECOND);
        return currentSecond;
    }

    /**
     * string change to date
     * @param strDate
     * @param dateFormat
     * @return date
     */
    public static Date toDate(String strDate, String dateFormat){
        if(strDate == null || strDate.length() == 0){
            return null;
        }
        Date date = null;
        DateFormat df = new SimpleDateFormat(dateFormat);
        try {
            date = df.parse(strDate);
        } catch (ParseException e) {
            e.printStackTrace();
        }
        return date;
    }

    /**
     * Returns this Calendar's time value in milliseconds
     * @param p_date
     * @return long
     */
    public static long getMillisOfDate(Date date) {
           cal.setTime(date);
           return cal.getTimeInMillis();
    }



    /**
     * compare two date
     * return the greater date
     * if equals return null
     * @param strStartDate
     * @param strEndDate
     * @return date
     */
    public static Date getGreaterDate(String strStartDate, String strEndDate){
        Date date = null;
        Date startDate = toDate(strStartDate, "yyyy-MM-dd");
        Date endDate = toDate(strEndDate, "yyyy-MM-dd");
        long startTime = getMillisOfDate(startDate);
        long endTime = getMillisOfDate(endDate);
        if((startTime - endTime) > 0){
            return startDate;
        }else if((endTime - startTime) > 0){
            return endDate;
        }
        return date;
    }

    /**
     * get days between 2 different date
     * @param strStartDate less date (yyyy-MM-dd)
     * @param strEndDate greater date (yyyy-MM-dd)
     * @return long
     */
    public static long getDaysOftwoDiffDate(String strStartDate, String strEndDate){
           Date startDate = toDate(strStartDate, "yyyy-MM-dd");
           Date endDate = toDate(strEndDate, "yyyy-MM-dd");
           long startTime = getMillisOfDate(startDate);
           long endTime = getMillisOfDate(endDate);
           long betweenDays = (long) ((endTime - startTime) / ( 1000 * 60 * 60 * 24 ));
           return betweenDays;
    }

    /**
     * get weeks between 2 different date
     * @param strStartDate less date (yyyy-MM-dd)
     * @param strEndDate greater date (yyyy-MM-dd)
     * @return long
     */
    public static long getWeeksOfTwoDiffDate(String strStartDate, String strEndDate){
        return getDaysOftwoDiffDate(strStartDate, strEndDate) / 7;
    }

    /**
     * get months between 2 different date
     * @param strStartDate less date (yyyy-MM-dd)
     * @param strEndDate greater date (yyyy-MM-dd)
     * @return long
     */
    public static long getMonthsOfTwoDiffDate(String strStartDate, String strEndDate){
        return getDaysOftwoDiffDate(strStartDate, strEndDate) / 30;
    }

    /**
     * get years between 2 different date
     * @param strStartDate less date (yyyy-MM-dd)
     * @param strEndDate greater date (yyyy-MM-dd)
     * @return long
     */
    public static long getYearsOfTwoDiffDate(String strStartDate, String strEndDate){
        return getDaysOftwoDiffDate(strStartDate, strEndDate) / 365;
    }

    /**
     * add date
     * @param date
     * @param count
     * @param field Calendar.YEAR(MONTH..)
     * @param format DateFormat(yyyy-MM-dd)
     * @return string
     */
    public static String addDate(Date date,int count,int field,String format){
           cal.setTime(date);
           int year = getYear();
           int month = getMonth() - 1;
           int day = getDay();
           int hours = getHours();
           int minutes = getMinutes();
           int seconds = getSeconds();
           Calendar calendar = new GregorianCalendar(year, month, day, hours, minutes, seconds);
           calendar.add(field,count);
           DateFormat df = new SimpleDateFormat(format);
           String tmpDate = df.format(calendar.getTime());
if(date == null){

cal.setTime(new Date());

}else{

cal.setTime(date);

}

           return tmpDate;
    }

    /**
     * calendar settime
     * @param date
     */
    private static void setCalTime(Date date){
        if(date != null){
            cal.setTime(date);
        }
    }

    //setter getter

    public static String getDefaultFormat() {
        return defaultFormat;
    }

    public static void setDefaultFormat(String defaultFormat) {
        SimpleDate.defaultFormat = defaultFormat;
    }

    public static Date getDate() {
        return date;
    }

    public static void setDate(Date date) {
        SimpleDate.date = date;
        setCalTime(date);
    }


}

kohri 2012-04-25 22:36 发表评论

关于date4j,��U�的日期处理�?Java's Date Classes Must Die.)

kohri — Wed, 11 Apr 2012 17:05:00 GMT

在熟悉公�怸�务代码的时候经常看见有日期处理�Q�date�Q?�׃��目转手�ơ数较多�Q�在�q�方面没合理��装处理好，于是��想自己��装一个date�c�R��然而辗转了几天却发觉已�l�有date4j的存在，于是在这里简单地介绍一下这个日期类库。以下包括自��q��代码、网上流传资料、以及date4j官网例子�?

-------------------------------------------------------------------------------------------------------------------------------------------------------------

java日期处理相关�c�：

java.util.Date
java.sql.Date
java.sql.Time
java.sql.Timestamp
java.util.Calendar
java.util.TimeZone

比较常用的是java.util.date�Q�将java.util.Date转�ؓjava.sql.Date的时候，日期时分�U�会被去掉，失去�_�ֺ�。而且如果现在��d��api看看��发觉这两个�c�d��多方法已�l�过�Ӟ��几近沦�ؓ废物�?/p>

Timestamp能和java.util.date无损转换�Q�但是在一些预定义sql中会常常出问题�?/p>

�Q�以上出�?nbsp;click me�Q?/p>

--------------------------------------------------------------------------------------------------------------------------------------------------------------

Java本��n的日期类在JDK1.0版本之后��再也没有更新过�Q�同时还存在着一些众所周知的问题（例如1月从0开始，��D��了很多月份差一的漏�z�）。一份新的Java规范��h��Q�JSR�Q�Java Specification Request�Q�已�l�被提交�Q�目的就是要解决上述问题�Q�此版本的类库仍处在Alpha版本。在其稳定之前，很多开发者还是会使用Joda Time�c�d��Q�该�c�d��与JSR-310的参考实现类��|��但不完全相同�Q��?Date4j为在Java中处理日期提供了一套新的解��x��案，但与Joda Time所��x��的范围完全不同。对比如下：

Joda Time	Date4j
拥有的类的数�? 140+	拥有的类的数�?a style="color: #0b59b2; ">< 10
包含可变和不可变�c?/td>	仅包含不可变�c?/td>
��速度和功�?/td>	��单和有效
支持格里高里历（Gregorian�Q��?�U�普特语日历�Q�Coptic�Q��?伊斯兰教历（Islamic�Q�、佛历（Buddhist�Q�等�{?/td>	只提供对格里高里历的支持
可以完全取代JDK日期�c?/td>	和JDK日期�c�配合��?/td>
�_��到毫�U��操作	支持到纳�U�（十亿分之一�U�）�U�操�?/strong>
修复了天“溢出”的问�?/td>	�?#8220;溢出”的问题可配置
针对的是通常意义的日期维�?/td>	适用于通过数据库来�l�护的日�?/td>
采用Apache 2.0授权许可	采用BSD授权许可

虽然乍一看Date4j只具备了Joda中一部分的特性，但它有两个主要的特点是Joda所不具备的�?/p>

首先�Q�Date4j的开发�?a target="_blank" style="color: #0b59b2; ">宣称�c�d��不应莫名其妙地将日期截断。Joda只支持毫�U��的精度而且在将�?a target="_blank" style="color: #0b59b2; ">可能也不会改�?/a>。一些数据库也已�l�有了更好的解决�Ҏ��。比如流行的PostgreSQL数据库对旉��戳精度就已经支持�?a target="_blank" style="color: #0b59b2; ">微秒�U?/a>�Q�百万分之一�U�）。Date4j可在处理日期时对�_�ֺ�毫无损伤�?/p>

�W�二个特征是日期“溢出”的问题，例如向某个日期增加一�D�|��间后�Q�日期落在下月的情况。最��单的例子��是�?�?1日增加一个月的计��：

DateTime dt = new DateTime("2011-03-31"); 

DateTime result = dt.plusMonths(1); (最新版本此�Ҏ��应该已经被删除，只有plus(...)与plusDay())

System.out.println(result.toString());

当��用Joda Time�Ӟ��会输�?�?0日，但这也许�q�不是你惌��的结果�?/p>

鉴于�q�种不确定性，Date4j为您提供�?a target="_blank" style="color: #0b59b2; ">4�U�选择�Q?/p>

1.	�W�一�?/td>
2.	最后一天（与Joda Time相同�Q?/td>
3.	日期��g
4.	抛出异常

以上转自 click me
-----------------------------------------------------------------------------------------------------------------------------------------------------------

date4j官网&&实例�Q?br />

import hirondelle.date4j.DateTime;
import hirondelle.date4j.DateTime.DayOverflow;

import java.util.TimeZone;

public class Date4jExamples {

    public static void main(String[] args) {
        Date4jExamples examples = new Date4jExamples();
        examples.currentDateTime();
        examples.ageIfBornOnCertainDate();
        examples.daysTillChristmas();
        examples.whenIs90DaysFromToday();
        examples.dateDifference();
        examples.whenIs3Months5DaysFromToday();
        examples.hoursDifferenceBetweenParisAndPerth();
        examples.weeksSinceStart();
        examples.timeTillMidnight();
        examples.imitateISOFormat();
        examples.firstDayOfThisWeek();
        examples.jdkDatesSuctorial();

    }

    private static void log(Object aMsg) {
        System.out.println(String.valueOf(aMsg));
    }

    /**
     * 获取当前旉�� what is the current date-time in the JRE's default time zone
     * ------------------------------------------------------------------------
     * Here are some practical examples of using the above formatting symbols:

     *
   *    Format                                  Output
   *   YYYY-MM-DD hh:mm:ss.fffffffff a    1958-04-09 03:05:06.123456789 AM
   *   YYYY-MM-DD hh:mm:ss.fff a             1958-04-09 03:05:06.123 AM
   *   YYYY-MM-DD                             1958-04-09
   *   hh:mm:ss.fffffffff                     03:05:06.123456789
   *   hh:mm:ss                             03:05:06
   *   YYYY-M-D h:m:s                         1958-4-9 3:5:6
   *   WWWW, MMMM D, YYYY                     Wednesday, April 9, 1958
   *   WWWW, MMMM D, YYYY |at| D a         Wednesday, April 9, 1958 at 3 AM
   *

     *----------------------------------------------------------------------
     * ---
    private void currentDateTime() {
        DateTime now = DateTime.now(TimeZone.getDefault());
        String result = now.format("YYYY-MM-DD hh:mm:ss");
        log("Current date-time in default time zone : " + result);
        // result Current date-time in default time zone : 2012-04-12 00:55:54
    }

    /**
     * �q�龄计算 what's the age of someone born may 16,1995
     */
    private void ageIfBornOnCertainDate() {
        DateTime today = DateTime.today(TimeZone.getDefault());
        DateTime birthdate = DateTime.forDateOnly(1995, 5, 16);
        int age = today.getYear() - birthdate.getYear();
        // getDayOfYear获取距离�q�初的��d��?/span>
        if (today.getDayOfYear() < birthdate.getDayOfYear()) {
            age = age - 1;
        }
        log("Age of someone born May 16, 1995 is : " + age);
        // result Age of someone born May 16, 1995 is : 16
    }

    /**
     * 日期相距 How many days till the next December 25
     */
    private void daysTillChristmas() {
        DateTime today = DateTime.today(TimeZone.getDefault());
        DateTime christmas = DateTime.forDateOnly(today.getYear(), 12, 25);
        int result = 0;
        if (today.isSameDayAs(christmas)) {
            // do nothing
        } else if (today.lt(christmas)) {
            result = today.numDaysFrom(christmas);
        } else if (today.gt(christmas)) {
            DateTime christmasNextYear = DateTime.forDateOnly(
                    today.getYear() + 1, 12, 25);
            result = today.numDaysFrom(christmasNextYear);
        }
        log("Number of days till Christmas : " + result);
        // result Number of days till Christmas : 257
    }

    /**
     * What day is 90 days from today
     */
    private void whenIs90DaysFromToday() {
        DateTime today = DateTime.today(TimeZone.getDefault());
        log("90 days from today is : "
                + today.plusDays(90).format("YYYY-MM-DD"));
        // result 90 days from today is : 2012-07-11
    }

    /**
     * 日期相差
     */
    private void dateDifference() {
        // DayOverflow.Abort result throw Exception
        // DayOverflow.Spillover result 2011-05-01
        // DayOverflow.LastDay result 2011-04-30
        // DayOverflow.FirstDay result 2011-05-01
        // public enum DayOverflow {
        /** Coerce the day to the last day of the month. */
        // LastDay,
        /** Coerce the day to the first day of the next month. */
        // FirstDay,
        /** Spillover the day into the next month. */
        // Spillover,
       /** Throw a RuntimeException. */
        // Abort;
        // }
        /**
         * @param aNumYears
         *            positive, required, in range 09999
         * @param aNumMonths
         *            positive, required, in range 09999
         * @param aNumDays
         *            positive, required, in range 09999
         * @param aNumHours
         *            positive, required, in range 09999
         * @param aNumMinutes
         *            positive, required, in range 09999
         * @param aNumSeconds
         *            positive, required, in range 09999 method plus(Integer
         *            aNumYears, Integer aNumMonths, Integer aNumDays, Integer
         *            aNumHours, Integer aNumMinutes, Integer aNumSeconds,
         *            DayOverflow aDayOverflow)
         *
         */
        DateTime dt = new DateTime("2011-03-31");
        DateTime result = dt.plus(0, 1, 0, 0, 0, 0, DayOverflow.Spillover);
        log("date difference : " + result.toString());
        // result date difference : 2011-05-01 00:00:00
    }

    /** What day is 3 months and 5 days from today? */
    private void whenIs3Months5DaysFromToday() {
        DateTime today = DateTime.today(TimeZone.getDefault());
        DateTime result = today.plus(0, 3, 5, 0, 0, 0,
                DateTime.DayOverflow.FirstDay);
        log("3 months and 5 days from today is : "
                + result.format("YYYY-MM-DD"));
        // result 3 months and 5 days from today is : 2012-07-17
    }

    /**
     * Current number of hours difference between Paris, France and Perth,
     * Australia.
     */
    private void hoursDifferenceBetweenParisAndPerth() {
        // this assumes the time diff is a whole number of hours; other styles
        // are possible
        DateTime paris = DateTime.now(TimeZone.getTimeZone("Europe/Paris"));
        DateTime perth = DateTime.now(TimeZone.getTimeZone("Australia/Perth"));
        int result = perth.getHour() - paris.getHour();
        if (result < 0) {
            result = result + 24;
        }
        log("Numbers of hours difference between Paris and Perth : " + result);
        // result Numbers of hours difference between Paris and Perth : 6
    }

    /** How many weeks is it since Sep 6, 2010? */
    private void weeksSinceStart() {
        DateTime today = DateTime.today(TimeZone.getDefault());
        DateTime startOfProject = DateTime.forDateOnly(2010, 9, 6);
        int result = today.getWeekIndex() - startOfProject.getWeekIndex();
        log("The number of weeks since Sep 6, 2010 : " + result);
        // result The number of weeks since Sep 6, 2010 : 83
    }

    /** How much time till midnight? */
    private void timeTillMidnight() {
        DateTime now = DateTime.now(TimeZone.getDefault());
        DateTime midnight = now.plusDays(1).getStartOfDay();
        long result = now.numSecondsFrom(midnight);
        log("This many seconds till midnight : " + result);
        // result This many seconds till midnight : 83046
    }

    /** Format using ISO style. */
    private void imitateISOFormat() {
        DateTime now = DateTime.now(TimeZone.getDefault());
        log("Output using an ISO format: " + now.format("YYYY-MM-DDThh:mm:ss"));
        // result Output using an ISO format: 2012-04-12T00:55:54
    }

    private void firstDayOfThisWeek() {
        DateTime today = DateTime.today(TimeZone.getDefault());
        DateTime firstDayThisWeek = today; // start value
        int todaysWeekday = today.getWeekDay();
        int SUNDAY = 1;
        if (todaysWeekday > SUNDAY) {
            int numDaysFromSunday = todaysWeekday - SUNDAY;
            firstDayThisWeek = today.minusDays(numDaysFromSunday);
        }
        log("The first day of this week is : " + firstDayThisWeek);
        // result The first day of this week is : 2012-04-08
    }

    /** For how many years has the JDK date-time API been suctorial? */
    private void jdkDatesSuctorial() {
        DateTime today = DateTime.today(TimeZone.getDefault());
        DateTime jdkFirstPublished = DateTime.forDateOnly(1996, 1, 23);
        int result = today.getYear() - jdkFirstPublished.getYear();
        log("The number of years the JDK date-time API has been suctorial : "
                + result);
        // result The number of years the JDK date-time API has been suctorial :
        // 16
    }
}

kohri 2012-04-12 01:05 发表评论

array_push 效率��试

kohri — Wed, 04 Apr 2012 10:01:00 GMT

在php中数�l�赋值的时候用array[]�q�种�Ҏ��效率会较高于array_push()�Q�于是乎各种�~�由��有了下面的��试
��试代码�Q?br />

php
    /**
        *数组性能��试
        *for循环遍历��试函数有性能影响所以没有用�Q�不同时调用2个函��C��是担心具有媄响，不封装同时执行代码是��h��影响�?br />        *��试是更�?count参数�Q�从10~100000 整取递增�Q�和调用�Ҏ��手动��h��Q�记录时间�ؓ�q�_��大概旉��
    **/
    $count = 10;
    arrayTest01($count);
    function arrayTest01($count) {
        $arr = array ();
        $time = microtime(true);
        for ($i = 0; $i < $count; $i++) {
            $array[] = $i;
        }
        echo (microtime(true) - $time);
    }
    function arrayTest02($count) {
        $arr = array ();
        $time = microtime(true);
        for ($i = 0; $i < $count; $i++) {
            array_push($arr, $i);
        }
        echo (microtime(true) - $time);
    }
?>

效率大概是array[]快将�q�一倍，��试环境是ubuntu 11 �?windows 7

windows php-5.2.17/ Apache2.2

times�Q?count�Q? 10 100 1000 10000　　　 100000　　　 1000000

array[] 2.31E-05 0.000104 0.000867 0.008417 0.043666 0.288323

array_push 2.79E-05 0.000181 0.001614 0.014447 0.055875 0.491052

ubuntu11.04 PHP 5.3.6/apache2.2

array[] 1.91E-05 7.70E-05 0.000726 0.007669 0.040492 报错

array_push 2.50E-05 1.26E-04 0.001149 0.013714 0.056978 报错

�q�是官方�|�站上的说辞

Note: 如果�?array_push() 来给数组增加一个单元，�q�不如用 $array[] = �Q�因��h��有调用函数的额外负担�?span style="white-space: pre;">
官网链接�Q?

http://cn.php.net/array_push

kohri 2012-04-04 18:01 发表评论

Linux SSH�q�程文�g/目录传输命��oscp [转]

kohri — Mon, 02 Apr 2012 07:23:00 GMT

scp使用�Ҏ��

1、获取远�E�服务器上的文�g

scp -P 2222 root@www.vpser.net:/root/lnmp0.4.tar.gz /home/lnmp0.4.tar.gz

上端口大写P 为参敎ͼ�2222 表示更改SSH端口后的端口�Q�如果没有更改SSH端口可以不用��d��该参数�? root@www.vpser.net 表示使用root用户��d��q�程服务器www.vpser.net�Q?/root/lnmp0.4.tar.gz 表示�q�程服务器上的文�Ӟ��最后面�?home/lnmp0.4.tar.gz表示保存在本��C��的�\径和文�g名�?/p>

2、获取远�E�服务器上的目录

scp -P 2222 -r root@www.vpser.net:/root/lnmp0.4/ /home/lnmp0.4/

上端口大写P 为参敎ͼ�2222 表示更改SSH端口后的端口�Q�如果没有更改SSH端口可以不用��d��该参数�?r 参数表示递归复制�Q�即复制该目录下面的文�g和目录）�Q�root@www.vpser.net 表示使用root用户��d��q�程服务器www.vpser.net�Q?/root/lnmp0.4/ 表示�q�程服务器上的目录，最后面�?home/lnmp0.4/表示保存在本��C��的�\径�?/p>

3、将本地文�g上传到服务器�?/h3>
scp -P 2222 /home/lnmp0.4.tar.gz root@www.vpser.net:/root/lnmp0.4.tar.gz

上端口大写P 为参敎ͼ�2222 表示更改SSH端口后的端口�Q�如果没有更改SSH端口可以不用��d��该参数�? /home/lnmp0.4.tar.gz表示本地上准备上传文件的路径和文件名。root@www.vpser.net 表示使用root用户��d��q�程服务器www.vpser.net�Q?/root/lnmp0.4.tar.gz 表示保存在远�E�服务器上目录和文�g名�?/p>

4、将本地目录上传到服务器�?/h3>
scp -P 2222 -r /home/lnmp0.4/ root@www.vpser.net:/root/lnmp0.4/

�?端口大写P 为参敎ͼ�2222 表示更改SSH端口后的端口�Q�如果没有更改SSH端口可以不用��d��该参数�?r 参数表示递归复制�Q�即复制该目录下面的文�g和目录）�Q?home/lnmp0.4/表示准备要上传的目录�Q�root@www.vpser.net 表示使用root用户��d��q�程服务器www.vpser.net�Q?/root/lnmp0.4/ 表示保存在远�E�服务器上的目录位置�?/p>

5、可能有用的几个参数 :

-v 和大多数 linux 命��o中的 -v 意思一�?, 用来昄��q�度 . 可以用来查看�q�接 , 认证 , 或是配置错误 .

-C 使能压羃选项 .

-4 ��使用 IPV4 地址 .

-6 ��使用 IPV6 地址 .

kohri 2012-04-02 15:23 发表评论