世事如棋
          Aspire to Professionalism
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          ?

          SQL中的單記錄函數(shù)
          1.ASCII
          返回與指定的字符對應(yīng)的十進制數(shù);
          SQL> select ascii('A') A,ascii('a') a,ascii('0') zero,ascii(' ') space from dual;

          ??????? A???????? A????? ZERO???? SPACE
          --------- --------- --------- ---------
          ?????? 65??????? 97??????? 48??????? 32


          2.CHR
          給出整數(shù),返回對應(yīng)的字符;
          SQL> select chr(54740) zhao,chr(65) chr65 from dual;

          ZH C
          -- -
          趙 A

          3.CONCAT
          連接兩個字符串;
          SQL> select concat('010-','88888888')||'轉(zhuǎn)23'? 高乾競電話 from dual;

          高乾競電話
          ----------------
          010-88888888轉(zhuǎn)23

          4.INITCAP
          返回字符串并將字符串的第一個字母變?yōu)榇髮?
          SQL> select initcap('smith') upp from dual;

          UPP
          -----
          Smith


          5.INSTR(C1,C2,I,J)
          在一個字符串中搜索指定的字符,返回發(fā)現(xiàn)指定的字符的位置;
          C1??? 被搜索的字符串
          C2??? 希望搜索的字符串
          I???? 搜索的開始位置,默認(rèn)為1
          J???? 出現(xiàn)的位置,默認(rèn)為1
          SQL> select instr('oracle traning','ra',1,2) instring from dual;

          ?INSTRING
          ---------
          ??????? 9


          6.LENGTH
          返回字符串的長度;
          SQL> select name,length(name),addr,length(addr),sal,length(to_char(sal)) from gao.nchar_tst;

          NAME?? LENGTH(NAME) ADDR???????????? LENGTH(ADDR)?????? SAL LENGTH(TO_CHAR(SAL))
          ------ ------------ ---------------- ------------ --------- --------------------
          高乾競??????????? 3 北京市海錠區(qū)??????????????? 6?? 9999.99??????????????????? 7

          ?

          7.LOWER
          返回字符串,并將所有的字符小寫
          SQL> select lower('AaBbCcDd')AaBbCcDd from dual;

          AABBCCDD
          --------
          aabbccdd


          8.UPPER
          返回字符串,并將所有的字符大寫
          SQL> select upper('AaBbCcDd') upper from dual;

          UPPER
          --------
          AABBCCDD

          ?

          9.RPAD和LPAD(粘貼字符)
          RPAD? 在列的右邊粘貼字符
          LPAD? 在列的左邊粘貼字符
          SQL> select lpad(rpad('gao',10,'*'),17,'*')from dual;

          LPAD(RPAD('GAO',1
          -----------------
          *******gao*******
          不夠字符則用*來填滿


          10.LTRIM和RTRIM
          LTRIM? 刪除左邊出現(xiàn)的字符串
          RTRIM? 刪除右邊出現(xiàn)的字符串
          SQL> select ltrim(rtrim('?? gao qian jing?? ',' '),' ') from dual;

          LTRIM(RTRIM('
          -------------
          gao qian jing


          11.SUBSTR(string,start,count)
          取子字符串,從start開始,取count個
          SQL> select substr('13088888888',3,8) from dual;

          SUBSTR('
          --------
          08888888


          12.REPLACE('string','s1','s2')
          string?? 希望被替換的字符或變量
          s1?????? 被替換的字符串
          s2?????? 要替換的字符串
          SQL> select replace('he love you','he','i') from dual;

          REPLACE('H
          ----------
          i love you


          13.SOUNDEX
          返回一個與給定的字符串讀音相同的字符串
          SQL> create table table1(xm varchar(8));
          SQL> insert into table1 values('weather');
          SQL> insert into table1 values('wether');
          SQL> insert into table1 values('gao');

          SQL> select xm from table1 where soundex(xm)=soundex('weather');

          XM
          --------
          weather
          wether


          14.TRIM('s' from 'string')
          LEADING?? 剪掉前面的字符
          TRAILING? 剪掉后面的字符
          如果不指定,默認(rèn)為空格符

          15.ABS
          返回指定值的絕對值
          SQL> select abs(100),abs(-100) from dual;

          ?ABS(100) ABS(-100)
          --------- ---------
          ????? 100?????? 100


          16.ACOS
          給出反余弦的值
          SQL> select acos(-1) from dual;

          ?ACOS(-1)
          ---------
          3.1415927


          17.ASIN
          給出反正弦的值
          SQL> select asin(0.5) from dual;

          ASIN(0.5)
          ---------
          .52359878


          18.ATAN
          返回一個數(shù)字的反正切值
          SQL> select atan(1) from dual;

          ? ATAN(1)
          ---------
          .78539816


          19.CEIL
          返回大于或等于給出數(shù)字的最小整數(shù)
          SQL> select ceil(3.1415927) from dual;

          CEIL(3.1415927)
          ---------------
          ????????????? 4


          20.COS
          返回一個給定數(shù)字的余弦
          SQL> select cos(-3.1415927) from dual;

          COS(-3.1415927)
          ---------------
          ???????????? -1


          21.COSH
          返回一個數(shù)字反余弦值
          SQL> select cosh(20) from dual;

          ?COSH(20)
          ---------
          242582598


          22.EXP
          返回一個數(shù)字e的n次方根
          SQL> select exp(2),exp(1) from dual;

          ?? EXP(2)??? EXP(1)
          --------- ---------
          7.3890561 2.7182818


          23.FLOOR
          對給定的數(shù)字取整數(shù)
          SQL> select floor(2345.67) from dual;

          FLOOR(2345.67)
          --------------
          ????????? 2345


          24.LN
          返回一個數(shù)字的對數(shù)值
          SQL> select ln(1),ln(2),ln(2.7182818) from dual;

          ??? LN(1)???? LN(2) LN(2.7182818)
          --------- --------- -------------
          ??????? 0 .69314718???? .99999999


          25.LOG(n1,n2)
          返回一個以n1為底n2的對數(shù)
          SQL> select log(2,1),log(2,4) from dual;

          ?LOG(2,1)? LOG(2,4)
          --------- ---------
          ??????? 0???????? 2


          26.MOD(n1,n2)
          返回一個n1除以n2的余數(shù)
          SQL> select mod(10,3),mod(3,3),mod(2,3) from dual;

          MOD(10,3)? MOD(3,3)? MOD(2,3)
          --------- --------- ---------
          ??????? 1???????? 0???????? 2


          27.POWER
          返回n1的n2次方根
          SQL> select power(2,10),power(3,3) from dual;

          POWER(2,10) POWER(3,3)
          ----------- ----------
          ?????? 1024???????? 27


          28.ROUND和TRUNC
          按照指定的精度進行舍入
          SQL> select round(55.5),round(-55.4),trunc(55.5),trunc(-55.5) from dual;

          ROUND(55.5) ROUND(-55.4) TRUNC(55.5) TRUNC(-55.5)
          ----------- ------------ ----------- ------------
          ???????? 56????????? -55????????? 55????????? -55


          29.SIGN
          取數(shù)字n的符號,大于0返回1,小于0返回-1,等于0返回0
          SQL> select sign(123),sign(-100),sign(0) from dual;

          SIGN(123) SIGN(-100)?? SIGN(0)
          --------- ---------- ---------
          ??????? 1???????? -1???????? 0


          30.SIN
          返回一個數(shù)字的正弦值
          SQL> select sin(1.57079) from dual;

          SIN(1.57079)
          ------------
          ?????????? 1


          31.SIGH
          返回雙曲正弦的值
          SQL> select sin(20),sinh(20) from dual;

          ? SIN(20)? SINH(20)
          --------- ---------
          .91294525 242582598


          32.SQRT
          返回數(shù)字n的根
          SQL> select sqrt(64),sqrt(10) from dual;

          ?SQRT(64)? SQRT(10)
          --------- ---------
          ??????? 8 3.1622777


          33.TAN
          返回數(shù)字的正切值
          SQL> select tan(20),tan(10) from dual;

          ? TAN(20)?? TAN(10)
          --------- ---------
          2.2371609 .64836083


          34.TANH
          返回數(shù)字n的雙曲正切值
          SQL> select tanh(20),tan(20) from dual;

          ?TANH(20)?? TAN(20)
          --------- ---------
          ??????? 1 2.2371609

          ?

          35.TRUNC
          按照指定的精度截取一個數(shù)
          SQL> select trunc(124.1666,-2) trunc1,trunc(124.16666,2) from dual;

          ?? TRUNC1 TRUNC(124.16666,2)
          --------- ------------------
          ????? 100???????????? 124.16

          ?

          36.ADD_MONTHS
          增加或減去月份
          SQL> select to_char(add_months(to_date('199912','yyyymm'),2),'yyyymm') from dual;

          TO_CHA
          ------
          200002
          SQL> select to_char(add_months(to_date('199912','yyyymm'),-2),'yyyymm') from dual;

          TO_CHA
          ------
          199910


          37.LAST_DAY
          返回日期的最后一天
          SQL> select to_char(sysdate,'yyyy.mm.dd'),to_char((sysdate)+1,'yyyy.mm.dd') from dual;

          TO_CHAR(SY TO_CHAR((S
          ---------- ----------
          2004.05.09 2004.05.10
          SQL> select last_day(sysdate) from dual;

          LAST_DAY(S
          ----------
          31-5月 -04


          38.MONTHS_BETWEEN(date2,date1)
          給出date2-date1的月份
          SQL> select months_between('19-12月-1999','19-3月-1999') mon_between from dual;

          MON_BETWEEN
          -----------
          ????????? 9
          SQL>selectmonths_between(to_date('2000.05.20','yyyy.mm.dd'),to_date('2005.05.20','yyyy.mm.dd')) mon_betw from dual;

          ?MON_BETW
          ---------
          ????? -60


          39.NEW_TIME(date,'this','that')
          給出在this時區(qū)=other時區(qū)的日期和時間
          SQL> select to_char(sysdate,'yyyy.mm.dd hh24:mi:ss') bj_time,to_char(new_time
          ? 2? (sysdate,'PDT','GMT'),'yyyy.mm.dd hh24:mi:ss') los_angles from dual;

          BJ_TIME???????????? LOS_ANGLES
          ------------------- -------------------
          2004.05.09 11:05:32 2004.05.09 18:05:32


          40.NEXT_DAY(date,'day')
          給出日期date和星期x之后計算下一個星期的日期
          SQL> select next_day('18-5月-2001','星期五') next_day from dual;

          NEXT_DAY
          ----------
          25-5月 -01

          ?

          41.SYSDATE
          用來得到系統(tǒng)的當(dāng)前日期
          SQL> select to_char(sysdate,'dd-mm-yyyy day') from dual;

          TO_CHAR(SYSDATE,'
          -----------------
          09-05-2004 星期日
          trunc(date,fmt)按照給出的要求將日期截斷,如果fmt='mi'表示保留分,截斷秒
          SQL> select to_char(trunc(sysdate,'hh'),'yyyy.mm.dd hh24:mi:ss') hh,
          ? 2? to_char(trunc(sysdate,'mi'),'yyyy.mm.dd hh24:mi:ss') hhmm from dual;

          HH????????????????? HHMM
          ------------------- -------------------
          2004.05.09 11:00:00 2004.05.09 11:17:00

          ?

          42.CHARTOROWID
          將字符數(shù)據(jù)類型轉(zhuǎn)換為ROWID類型
          SQL> select rowid,rowidtochar(rowid),ename from scott.emp;

          ROWID????????????? ROWIDTOCHAR(ROWID) ENAME
          ------------------ ------------------ ----------
          AAAAfKAACAAAAEqAAA AAAAfKAACAAAAEqAAA SMITH
          AAAAfKAACAAAAEqAAB AAAAfKAACAAAAEqAAB ALLEN
          AAAAfKAACAAAAEqAAC AAAAfKAACAAAAEqAAC WARD
          AAAAfKAACAAAAEqAAD AAAAfKAACAAAAEqAAD JONES


          43.CONVERT(c,dset,sset)
          將源字符串 sset從一個語言字符集轉(zhuǎn)換到另一個目的dset字符集
          SQL> select convert('strutz','we8hp','f7dec') "conversion" from dual;

          conver
          ------
          strutz


          44.HEXTORAW
          將一個十六進制構(gòu)成的字符串轉(zhuǎn)換為二進制


          45.RAWTOHEXT
          將一個二進制構(gòu)成的字符串轉(zhuǎn)換為十六進制

          ?

          46.ROWIDTOCHAR
          將ROWID數(shù)據(jù)類型轉(zhuǎn)換為字符類型

          ?

          47.TO_CHAR(date,'format')
          SQL> select to_char(sysdate,'yyyy/mm/dd hh24:mi:ss') from dual;

          TO_CHAR(SYSDATE,'YY
          -------------------
          2004/05/09 21:14:41

          ?

          48.TO_DATE(string,'format')
          將字符串轉(zhuǎn)化為ORACLE中的一個日期


          49.TO_MULTI_BYTE
          將字符串中的單字節(jié)字符轉(zhuǎn)化為多字節(jié)字符
          SQL>? select to_multi_byte('高') from dual;

          TO
          --


          50.TO_NUMBER
          將給出的字符轉(zhuǎn)換為數(shù)字
          SQL> select to_number('1999') year from dual;

          ???? YEAR
          ---------
          ???? 1999


          51.BFILENAME(dir,file)
          指定一個外部二進制文件
          SQL>insert into file_tb1 values(bfilename('lob_dir1','image1.gif'));


          52.CONVERT('x','desc','source')
          將x字段或變量的源source轉(zhuǎn)換為desc
          SQL> select sid,serial#,username,decode(command,
          ? 2? 0,'none',
          ? 3? 2,'insert',
          ? 4? 3,
          ? 5? 'select',
          ? 6? 6,'update',
          ? 7? 7,'delete',
          ? 8? 8,'drop',
          ? 9? 'other') cmd? from v$session where type!='background';

          ????? SID?? SERIAL# USERNAME?????????????????????? CMD
          --------- --------- ------------------------------ ------
          ??????? 1???????? 1??????????????????????????????? none
          ??????? 2???????? 1??????????????????????????????? none
          ??????? 3???????? 1??????????????????????????????? none
          ??????? 4???????? 1??????????????????????????????? none
          ??????? 5???????? 1??????????????????????????????? none
          ??????? 6???????? 1??????????????????????????????? none
          ??????? 7????? 1275??????????????????????????????? none
          ??????? 8????? 1275??????????????????????????????? none
          ??????? 9??????? 20 GAO??????????????????????????? select
          ?????? 10??????? 40 GAO??????????????????????????? none


          53.DUMP(s,fmt,start,length)
          DUMP函數(shù)以fmt指定的內(nèi)部數(shù)字格式返回一個VARCHAR2類型的值
          SQL> col global_name for a30
          SQL> col dump_string for a50
          SQL> set lin 200
          SQL> select global_name,dump(global_name,1017,8,5) dump_string from global_name;

          GLOBAL_NAME??????????????????? DUMP_STRING
          ------------------------------ --------------------------------------------------
          ORACLE.WORLD?????????????????? Typ=1 Len=12 CharacterSet=ZHS16GBK: W,O,R,L,D


          54.EMPTY_BLOB()和EMPTY_CLOB()
          這兩個函數(shù)都是用來對大數(shù)據(jù)類型字段進行初始化操作的函數(shù)


          55.GREATEST
          返回一組表達式中的最大值,即比較字符的編碼大小.
          SQL> select greatest('AA','AB','AC') from dual;

          GR
          --
          AC
          SQL> select greatest('啊','安','天') from dual;

          GR
          --


          56.LEAST
          返回一組表達式中的最小值
          SQL> select least('啊','安','天') from dual;

          LE
          --


          57.UID
          返回標(biāo)識當(dāng)前用戶的唯一整數(shù)
          SQL> show user
          USER 為"GAO"
          SQL> select username,user_id from dba_users where user_id=uid;

          USERNAME???????????????????????? USER_ID
          ------------------------------ ---------
          GAO?????????????????????????????????? 25

          ?

          58.USER
          返回當(dāng)前用戶的名字
          SQL> select user from? dual;

          USER
          ------------------------------
          GAO


          59.USEREVN
          返回當(dāng)前用戶環(huán)境的信息,opt可以是:
          ENTRYID,SESSIONID,TERMINAL,ISDBA,LABLE,LANGUAGE,CLIENT_INFO,LANG,VSIZE
          ISDBA? 查看當(dāng)前用戶是否是DBA如果是則返回true
          SQL> select userenv('isdba') from dual;

          USEREN
          ------
          FALSE
          SQL> select userenv('isdba') from dual;

          USEREN
          ------
          TRUE
          SESSION
          返回會話標(biāo)志
          SQL> select userenv('sessionid') from dual;

          USERENV('SESSIONID')
          --------------------
          ???????????????? 152
          ENTRYID
          返回會話人口標(biāo)志
          SQL> select userenv('entryid') from dual;

          USERENV('ENTRYID')
          ------------------
          ???????????????? 0
          INSTANCE
          返回當(dāng)前INSTANCE的標(biāo)志
          SQL> select userenv('instance') from dual;

          USERENV('INSTANCE')
          -------------------
          ????????????????? 1
          LANGUAGE
          返回當(dāng)前環(huán)境變量
          SQL> select userenv('language') from dual;

          USERENV('LANGUAGE')
          ----------------------------------------------------
          SIMPLIFIED CHINESE_CHINA.ZHS16GBK
          LANG
          返回當(dāng)前環(huán)境的語言的縮寫
          SQL> select userenv('lang') from dual;

          USERENV('LANG')
          ----------------------------------------------------
          ZHS
          TERMINAL
          返回用戶的終端或機器的標(biāo)志
          SQL> select userenv('terminal') from dual;

          USERENV('TERMINA
          ----------------
          GAO
          VSIZE(X)
          返回X的大小(字節(jié))數(shù)
          SQL> select vsize(user),user from dual;

          VSIZE(USER) USER
          ----------- ------------------------------
          ????????? 6 SYSTEM

          ?

          60.AVG(DISTINCT|ALL)
          all表示對所有的值求平均值,distinct只對不同的值求平均值
          SQLWKS> create table table3(xm varchar(8),sal number(7,2));
          語句已處理。
          SQLWKS>? insert into table3 values('gao',1111.11);
          SQLWKS>? insert into table3 values('gao',1111.11);
          SQLWKS>? insert into table3 values('zhu',5555.55);
          SQLWKS> commit;

          SQL> select avg(distinct sal) from gao.table3;

          AVG(DISTINCTSAL)
          ----------------
          ???????? 3333.33

          SQL> select avg(all sal) from gao.table3;

          AVG(ALLSAL)
          -----------
          ??? 2592.59


          61.MAX(DISTINCT|ALL)
          求最大值,ALL表示對所有的值求最大值,DISTINCT表示對不同的值求最大值,相同的只取一次
          SQL> select max(distinct sal) from scott.emp;

          MAX(DISTINCTSAL)
          ----------------
          ??????????? 5000


          62.MIN(DISTINCT|ALL)
          求最小值,ALL表示對所有的值求最小值,DISTINCT表示對不同的值求最小值,相同的只取一次
          SQL> select min(all sal) from gao.table3;

          MIN(ALLSAL)
          -----------
          ??? 1111.11


          63.STDDEV(distinct|all)
          求標(biāo)準(zhǔn)差,ALL表示對所有的值求標(biāo)準(zhǔn)差,DISTINCT表示只對不同的值求標(biāo)準(zhǔn)差
          SQL> select stddev(sal) from scott.emp;

          STDDEV(SAL)
          -----------
          ? 1182.5032

          SQL> select stddev(distinct sal) from scott.emp;

          STDDEV(DISTINCTSAL)
          -------------------
          ?????????? 1229.951

          ?

          64.VARIANCE(DISTINCT|ALL)
          求協(xié)方差

          SQL> select variance(sal) from scott.emp;

          VARIANCE(SAL)
          -------------
          ??? 1398313.9


          65.GROUP BY
          主要用來對一組數(shù)進行統(tǒng)計
          SQL> select deptno,count(*),sum(sal) from scott.emp group by deptno;

          ?? DEPTNO? COUNT(*)? SUM(SAL)
          --------- --------- ---------
          ?????? 10???????? 3????? 8750
          ?????? 20???????? 5???? 10875
          ?????? 30???????? 6????? 9400

          ?

          66.HAVING
          對分組統(tǒng)計再加限制條件
          SQL> select deptno,count(*),sum(sal) from scott.emp group by deptno having count(*)>=5;

          ?? DEPTNO? COUNT(*)? SUM(SAL)
          --------- --------- ---------
          ?????? 20???????? 5???? 10875
          ?????? 30???????? 6????? 9400
          SQL> select deptno,count(*),sum(sal) from scott.emp having count(*)>=5 group by deptno ;

          ?? DEPTNO? COUNT(*)? SUM(SAL)
          --------- --------- ---------
          ?????? 20???????? 5???? 10875
          ?????? 30???????? 6????? 9400


          67.ORDER BY
          用于對查詢到的結(jié)果進行排序輸出
          SQL> select deptno,ename,sal from scott.emp order by deptno,sal desc;

          ?? DEPTNO ENAME??????????? SAL
          --------- ---------- ---------
          ?????? 10 KING??????????? 5000
          ?????? 10 CLARK?????????? 2450
          ?????? 10 MILLER????????? 1300
          ?????? 20 SCOTT?????????? 3000
          ?????? 20 FORD??????????? 3000
          ?????? 20 JONES?????????? 2975
          ?????? 20 ADAMS?????????? 1100
          ?????? 20 SMITH??????????? 800
          ?????? 30 BLAKE?????????? 2850
          ?????? 30 ALLEN?????????? 1600
          ?????? 30 TURNER????????? 1500
          ?????? 30 WARD??????????? 1250
          ?????? 30 MARTIN????????? 1250
          ?????? 30 JAMES??????????? 950


          作者Blog: http://blog.csdn.net/AustinLei/
          posted on 2006-05-12 10:06 KingWell 閱讀(154) 評論(0)  編輯  收藏 所屬分類: Hibernate

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