qqjianyue代碼工

Pattern類：
例子：
        Pattern pattern = Pattern.compile("[,\\s]+");
        String[] result = pattern.split("one two three,four,five, six");
        for(int i = 0; i<result.length; i++){
            System.out.println(result[i]);
        }
輸出結(jié)果是：
one
two
three
four
five
six
Pattern類的靜態(tài)方法compile用來(lái)編譯正則表達(dá)式，在此[,\\s]+表示若干個(gè)","或者若干個(gè)空格匹配
split方法使用正則匹配將字符串切割成各子串并且返回

Matcher類：
注意，Matcher的獲得是通過(guò)Pattern.matcher(CharSequence charSequence);輸入必須是實(shí)現(xiàn)了CharSequence接口的類
常用方法：
matches()判斷整個(gè)輸入串是否匹配，整個(gè)匹配則返回true
例如下面會(huì)輸出true
        String str1 = "hello";
        Pattern pattern1 = Pattern.compile("hello");
        Matcher matcher1 = pattern1.matcher(str1);
        System.out.println(matcher1.matches());

lookingAt()從頭開(kāi)始尋找，找到匹配則返回true
例如下面會(huì)輸出true
        String str2 = "hello yangfan!";
        Pattern pattern2 = Pattern.compile("hello");
        Matcher matcher2 = pattern2.matcher(str2);
        System.out.println(matcher2.lookingAt());

find()掃描輸入串，尋找下一個(gè)匹配子串，存在則返回true
例如下面將會(huì)將所有no替換成yes
        Pattern pattern = Pattern.compile("no");
        Matcher matcher = pattern.matcher("Does jianyue love yangfan? no;" +
                "Does jianyue love yangfan? no;Does jianyue love yangfan? no;");
        StringBuffer sb = new StringBuffer();
        boolean find = matcher.find();
        while(find){
            matcher.appendReplacement(sb, "yes");
            find = matcher.find();
        }
        matcher.appendTail(sb);
        System.out.println(sb.toString());