Mon, 15 Mar 2010 03:16:00 GMT

摘要: HashMap&Hashtable: Map接口的实现类,��惟一键映��到特定的��g��:. HashMap 允许key或value为null. Hashtable的方法是Synchronize�?多个�U�程讉K��Hashtable�?不需要�ؓ�Ҏ��实现同步. Collection &Collections: Col... 阅读全文

Wed, 11 Nov 2009 05:17:00 GMT

//生��?消费�?问题

public class Pro_Cus {

public static void main(String[] args){

  Container con=new Container();

  Producer p=new Producer(con);
  Customer c=new Customer(con);

  new Thread(p).start();//各定义了两个�U�程�Q�可以多个线�E?br />   new Thread(c).start();
  new Thread(p).start();
  new Thread(c).start();
}

}
//产品
class Product{

int id;
public Product(int id){
  this.id=id;
}

public String toString(){
  return ""+this.id;
}

}
//装��品容�?br /> class Container{
Product[] num=new Product[10];
int index=0;

public synchronized void push(Product pro){

  while(index==num.length){
   try {
    this.wait();
   } catch (InterruptedException e) {
    e.printStackTrace();
   }
  }
  this.notifyAll(); //倘若只有一个消费线�E�则�Q�用this.notify();
  num[index]=pro;
  index++;
}

public synchronized Product pop(){

  while(index==0){
   try {
    this.wait();
   } catch (InterruptedException e) {
    e.printStackTrace();
   }
  }
  this.notifyAll();//倘若只有一个生产者线�E�，用this.notify
    index--;
    return num[index];

}

}

//生��?br /> class Producer implements Runnable{

Container con=null;

public Producer(Container con){
  this.con=con;
}
public void run(){
    for(int i=0;i<20;i++){

     try {
   Thread.sleep(10); //10毫秒生��一�?br />   } catch (InterruptedException e) {
   e.printStackTrace();
  }
     con.push(new Product(i));

     System.out.println("生��了��品："+i);
    }
}

}

//消费�?br /> class Customer implements Runnable{

Container con=null;

public Customer(Container con){
  this.con=con;
}
public void run(){
    for(int i=0;i<20;i++){

     try {
    Thread.sleep((int)(Math.random()*3000));//随机��于�{�于3�U�消费一�?br />    //Thread.sleep(3000);//�?�U�消费一个用�Q�这�U��Ş�?br />   } catch (InterruptedException e) {
   e.printStackTrace();
  }
     Product pro=con.pop();
     System.out.println("消费了��品："+pro);
    }
}

}

��d��?/a> 2009-11-11 13:17 发表评论

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