IBMSOFT

          ibmsoft 努力不一定成功,放棄一定失敗! 堅持自己的理想,實現(xiàn)自己的目標! 有好的想法就要出想辦法實現(xiàn)!

          BlogJava 首頁 新隨筆 聯(lián)系 聚合 管理
            8 Posts :: 2 Stories :: 3 Comments :: 0 Trackbacks

          2006年6月28日 #

          http://www.aygfsteel.com/youxia/archive/2007/03/01/101320.html
          posted @ 2007-03-05 23:40 ibmsoft 閱讀(104) | 評論 (0)編輯 收藏

          http://forum.springside.org.cn/viewthread.php?tid=927&highlight=%E6%9D%83%E9%99%90
          簡單實用一分鐘上手級權限控制

          找回來自己以前的一個項目, 用的是通過filter過濾來管理權限的方法, 很簡單,但也很實用。 這個項目并不小,但這么一個類就已經(jīng)可以滿足其權限管理的需要了,所以其實很多時候,權限管理大家并不必要想得那么復雜, 對于不少系統(tǒng),簡單通過filter來管理就ok了, simple 也是一種美^_^ 在web.xml里加入

          1. <!--================權限?設置================-->??
          2. <filter>??
          3. ????<filter-name>Authentication</filter-name>??
          4. ????<filter-class>com.springside.demo.security.UrlFilter</filter-class>??
          5. ????<init-param>??
          6. ????????<param-name>onError</param-name>??
          7. ????????<param-value>/login.jsp</param-value>??
          8. ????</init-param>??
          9. </filter>??
          10. <filter-mapping>??
          11. ????<filter-name>Authentication</filter-name>??
          12. ????<!--?只過濾?.jsp?結尾的url,?其余的如?.do,?.html,?.jpg,?.css?等不作過濾-->??
          13. ????<url-pattern>*.jsp</url-pattern>??
          14. </filter-mapping>??

          ?

          UrlFilter filter類的實現(xiàn)

          1. public?class?UrlFilter?implements?Filter?{??
          2. ????private?FilterConfig?filterConfig;??
          3. ??
          4. ????private?FilterChain?chain;??
          5. ??
          6. ????private?HttpServletRequest?request;??
          7. ??
          8. ????private?HttpServletResponse?response;??
          9. ??
          10. ????public?void?destroy()?{??
          11. ????????this.filterConfig?=?null;??
          12. ????}??
          13. ??
          14. ????public?void?init(FilterConfig?filterConfig)?throws?ServletException?{??
          15. ????????this.filterConfig?=?filterConfig;??
          16. ????}??
          17. ??
          18. ????public?void?doFilter(ServletRequest?servletRequest,??
          19. ????????????ServletResponse?servletResponse,?FilterChain?chain)??
          20. ????????????throws?IOException,?ServletException?{??
          21. ????????this.chain?=?chain;??
          22. ????????this.request?=?(HttpServletRequest)?servletRequest;??
          23. ????????this.response?=?((HttpServletResponse)?servletResponse);??
          24. ??
          25. ????????String?url?=?request.getServletPath();??
          26. ????????if?(url?==?null)??
          27. ????????????url?=?"";??
          28. ??
          29. ????????//?獲取session中的loginuser對象??
          30. ????????HttpSession?session?=?request.getSession();??
          31. ????????LoginUser?loginuser?=?(LoginUser)?session.getAttribute("loginuser");??
          32. ??
          33. ????????if?(baseUrl(url,?request))?{??
          34. ????????????//?如果是登陸界面等無須<u><b><font?color="#FF0000">權限</font></b></u>訪問的的公用界面則跳過??
          35. ????????????chain.doFilter(request,?response);??
          36. ????????}?else?if?(loginuser?==?null)?{??
          37. ????????????checkLogin(url);??
          38. ????????}?else?{??
          39. ????????????verifyUrl(url,?loginuser);??
          40. ????????}??
          41. ????}??
          42. ??
          43. ????private?void?checkLogin(String?url)?throws?ServletException,?IOException?{??
          44. ????????//?如果session中獲取不到?loginuser?對象,要不就是session?過期了,要不就是還沒登陸。所以返回登陸界面??
          45. ????????//?在登陸后記得把?loginuser?對象置于?session中??
          46. ??
          47. ????????if?(url.indexOf("/index.jsp")?>=?0??
          48. ????????????????&&?"login".equals(request.getParameter("act")))?{??
          49. ????????????//?獲取request中username,password??
          50. ????????????String?username?=?request.getParameter("username");??
          51. ????????????String?password?=?request.getParameter("password");??
          52. ????????????UserDao?userDao?=?new?UserDao();??
          53. ????????????if?(userDao.authUser(username,?password))?{??
          54. ????????????????LoginUser?user?=?userDao.getUser(username);??
          55. ????????????????request.getSession().setAttribute("loginuser",?user);??
          56. ????????????????verifyUrl(url,user);??
          57. ????????????????return;??
          58. ????????????}??
          59. ????????}??
          60. ????????response.sendRedirect("login.jsp");??
          61. ????}??
          62. ??
          63. ????private?void?verifyUrl(String?url,?LoginUser?loginuser)??
          64. ????????????throws?IOException,?ServletException?{??
          65. ????????//?獲取?loginuser?擁有的所有資源串??
          66. ????????Set?royurl?=?loginuser.getResStrings();??
          67. ????????if?(royurl?!=?null?&&?royurl.size()?>?0?&&?pass(royurl,?url,?request.getParameterMap()))?{??
          68. ????????????chain.doFilter(request,?response);??
          69. ????????}?else?{??
          70. ????????????response.setContentType("text/html;charset=GBK");??
          71. ????????????response??
          72. ????????????????????.getWriter()??
          73. ????????????????????.println(??
          74. ????????????????????????????"<div?style='margin:?100?auto;text-align:?center;"??
          75. ????????????????????????????????????+?"font:?bold?18px?宋體;color:?#0066CC;vertical-align:?middle'>?Sorry,您沒有<u><b><font?color="#FF0000">權限</font></b></u>訪問該資源!</div>");??
          76. ????????}??
          77. ????}??
          78. ??
          79. ????/**?
          80. ?????*?判斷是否是公用界面?
          81. ?????*/??
          82. ????protected?boolean?baseUrl(String?url,?HttpServletRequest?request)?{??
          83. ????????if?(url.indexOf("/login.jsp")?>=?0)?{??
          84. ????????????return?true;??
          85. ????????}??
          86. ????????return?false;??
          87. ????}??
          88. ??
          89. ????/**?
          90. ?????*?判斷該用戶是否有權請求該url?
          91. ?????*??
          92. ?????*?@param?royurl?
          93. ?????*????????????user擁有的授權的的url串集合?
          94. ?????*?@param?url?
          95. ?????*????????????當前請求的url?
          96. ?????*?@param?reqmap?
          97. ?????*????????????當前request的參數(shù)?
          98. ?????*?@return?是否通過該url?
          99. ?????*/??
          100. ????protected?boolean?pass(Set?royurl,?String?url,?Map?reqmap)?{??
          101. ????????boolean?match?=?true;??
          102. ????????for?(Iterator?iter?=?royurl.iterator();?iter.hasNext();)?{??
          103. ????????????//?獲取資源??
          104. ????????????match?=?true;??
          105. ????????????String?res_string?=?(String)?iter.next();??
          106. ????????????if?(res_string.indexOf("*")?>?0)?{??
          107. ????????????????res_string?=?res_string.substring(0,?res_string.indexOf("*"));??
          108. ????????????????if?(url.substring(0,?res_string.length()).equalsIgnoreCase(??
          109. ????????????????????????res_string))?{??
          110. ????????????????????return?true;?//?增加通配符比較??
          111. ????????????????}??
          112. ????????????}??
          113. ????????????//?分割url與參數(shù)??
          114. ????????????String[]?spw?=?res_string.split("\\?");?//?用"\\?"?轉(zhuǎn)義后即可得到正確的結??
          115. ????????????if?(!url.equalsIgnoreCase(spw[0]))?{??
          116. ????????????????match?=?false;??
          117. ????????????}??
          118. ????????????if?(match?&&?spw.length?>?1)?{??
          119. ????????????????String[]?spa?=?spw[1].split("\\&");?//?分拆各參數(shù)??
          120. ????????????????for?(int?j?=?0;?j?<?spa.length;?j++)?{??
          121. ????????????????????String[]?spe?=?spa[j].split("=");?//?分拆鍵與值??
          122. ????????????????????String?key?=?spe[0];??
          123. ????????????????????String?value?=?"";??
          124. ????????????????????if?(spe.length?>?1)?{??
          125. ????????????????????????value?=?spe[1].trim();??
          126. ????????????????????}??
          127. ??
          128. ????????????????????//?輪詢??
          129. ????????????????????String[]?values?=?(String[])?reqmap.get(key);??
          130. ????????????????????if?(values?!=?null)?{??
          131. ????????????????????????for?(int?k?=?0;?k?<?values.length;?k++)?{??
          132. ????????????????????????????if?(value.equalsIgnoreCase(values[k]))?{??
          133. ????????????????????????????????match?=?true;??
          134. ????????????????????????????????break;??
          135. ????????????????????????????}??
          136. ????????????????????????????match?=?false;??
          137. ????????????????????????}??
          138. ????????????????????????if?(!match)?{??
          139. ????????????????????????????break;??
          140. ????????????????????????}??
          141. ????????????????????}??
          142. ????????????????}??
          143. ??
          144. ????????????}??
          145. ??
          146. ????????????if?(match)?{??
          147. ????????????????break;??
          148. ????????????}??
          149. ????????}??
          150. ????????return?match;??
          151. ????}??
          152. ??
          153. ????public?static?void?main(String[]?args)?{??
          154. ????????UrlFilter?filter?=?new?UrlFilter();??
          155. ????????String?url?=?"/baseProd/product.do";??
          156. ??
          157. ????????Map?reqmap?=?new?HashMap();??
          158. ????????//?當前請求productline參數(shù)是11,12??
          159. ????????reqmap.put("productline",?new?String[]?{?"11",?"12"?});??
          160. ??
          161. ????????String?str;??
          162. ????????Set?royurl?=?new?HashSet();??
          163. ??
          164. ????????//?和授權的的url根本不同,false??
          165. ????????royurl.add("/user.do?a=1&b=2");??
          166. ????????System.out.println("match?false:"?+?filter.pass(royurl,?url,?reqmap));??
          167. ????????//?授權的請求參數(shù)13,14時?false??
          168. ????????royurl.add("/baseProd/product.do?productline=13&productline=14");??
          169. ????????System.out.println("match?false:"?+?filter.pass(royurl,?url,?reqmap));??
          170. ????????//?授權的請求參數(shù)11,13時?false??
          171. ????????royurl.add("/baseProd/product.do?productline=11&productline=13");??
          172. ????????System.out.println("match?false:"?+?filter.pass(royurl,?url,?reqmap));??
          173. ??
          174. ????????//?授權的請求參數(shù)11時?true??
          175. ????????royurl.add("/baseProd/product.do?productline=11");??
          176. ????????System.out.println("match?true:"?+?filter.pass(royurl,?url,?reqmap));??
          177. ??
          178. ????????//?參數(shù)的不論順序?true??
          179. ????????royurl.add("/baseProd/product.do?productline=12&productline=11");??
          180. ????????System.out.println("match?true:"?+?filter.pass(royurl,?url,?reqmap));??
          181. ??
          182. ????????royurl.clear();??
          183. ????????//?支持?"*"?號作通配符?true??
          184. ????????royurl.add("/baseProd/product.do*");??
          185. ????????System.out.println("match?ture:"?+?filter.pass(royurl,?url,?reqmap));??
          186. ??
          187. ????}??
          188. ??
          189. }??
          LoginUser 類:
          1. public?class?LoginUser?{??
          2. ????private?String?name;??
          3. ??????
          4. ????//用戶的授權url集合,如"/product.do?line=1&singer=2","/menu.do?son=1&son=2&son=3","/job.do*"??
          5. ????private?Set?resStrings;??
          6. ??
          7. ????public?String?getName()?{??
          8. ????????return?name;??
          9. ????}??
          10. ??
          11. ????public?void?setName(String?name)?{??
          12. ????????this.name?=?name;??
          13. ????}??
          14. ??
          15. ????public?Set?getResStrings()?{??
          16. ????????return?resStrings;??
          17. ????}??
          18. ??
          19. ????public?void?setResStrings(Set?resStrings)?{??
          20. ????????this.resStrings?=?resStrings;??
          21. ????}??
          22. ??????
          23. ??????
          24. }?

          posted @ 2007-03-05 23:38 ibmsoft 閱讀(270) | 評論 (0)編輯 收藏

          http://blog.chinaunix.net/u/11262/showart_213703.html
          http://wiki.springside.org.cn/display/springside/Acegi+Reference

          RBAC初學筆記

          什么是RBAC

          RBAC就是Role-Based Access Control,基于角色的訪問控制。角色訪問控制(RBAC)引入了Role的概念,目的是為了隔離User(即動作主體,Subject)Privilege(權限,表示對Resource的一個操作,即Operation+Resource),更符合企業(yè)的用戶、組織、數(shù)據(jù)和應用特征。

          RBAC的關注點在于Roleuser,Roleprivilege的關系,也就是User AssignmentPermission Assignment的關系。

          RBAC有以下優(yōu)點:

          1減少授權管理的復雜性,降低管理開銷
            2、靈活的支持企業(yè)的安全策略,對企業(yè)的變化有很大的伸縮性

          ?

          解決復雜的權限管理問題的過程可以抽象概括為:判斷【Who是否可以對What進行How的訪問操作(Operator】這個邏輯表達式的值是否為True的求解過程。

          RBAC中的幾個重要概念:

          l???????? Who權限的擁有者或主體。典型的有PrincipalUser、GroupRole、Actor等等。跟授權有關系的實體就只有角色(Role)和用戶(User)。譬如:業(yè)務經(jīng)理(Role),張三(User

          Role作為一個用戶(User)與權限(Privilege)的代理層,解耦了權限和用戶的關系,所有的授權應該給予Role而不是直接給UserGroup?;诮巧脑L問控制方法的思想就是把對用戶的授權分成兩部份,用角色來充當用戶行駛權限的中介。角色是一組訪問權限的集合,一個用戶可以是很多角色的成員,一個角色也可以有很多個權限,而一個權限也可以重復配置于多個角色。

          User用戶就是一個可以獨立訪問計算機系統(tǒng)中的數(shù)據(jù)或者用數(shù)據(jù)表示的其它資源的主體,我們用USERS表示一個用戶集合。用戶在一般情況下是指人。

          Group:是一組相關user的集合。Usergroup繼承出來,也就具有了該group的角色權限。

          個人覺得可以這么認為,role是抽象化了的usergroup。

          l???????? What權限針對的資源(Resource)(包括資源類別(the type of Resource)和資源實例(the instance of Resource))。譬如:報表。

          粗粒度:表示類別級,即僅考慮對象的類別(the type of object),不考慮對象的某個特定實例。比如,用戶管理中,創(chuàng)建、刪除,對所有的用戶都一視同仁,并不區(qū)分操作的具體對象實例。

          細粒度:表示實例級,即需要考慮具體對象的實例(the instance of object),當然,細粒度是在考慮粗粒度的對象類別之后才再考慮特定實例。比如,合同管理中,列表、刪除,需要區(qū)分該合同實例是否為當前用戶所創(chuàng)建。

          l???????? How亦作action,表示某種訪問方法(亦請參考Operator條目解釋)。譬如:刪除。

          l? Operator操作。表示施加于WhatHow動作。是一種Resource Related的概念,單獨的How動作是沒有實際意義的,譬如:刪除;只有與具體資源結合在一起才有意義,譬如:刪除報表。

          下面的圖展示了user,group,role,how的關系

          ?

          權限系統(tǒng)的核心由以下三部分構成:

          1.????? 創(chuàng)造權限

          2.?????? 分配權限

          3.?????? 使用權限

          ?

          系統(tǒng)各部分的主要參與者對照如下:

          1.創(chuàng)造權限 - Programer創(chuàng)造,

          2.分配權限 - Administrator 分配,

          3.使用權限– User

          ?

          ?
          1. Programer 向權限系統(tǒng)提供 Operator = Privilege + Resource
          2. Administrator 利用 Operator 這個基本元素,來創(chuàng)造他理想中的權限模型。
            如,創(chuàng)建角色,創(chuàng)建用戶組,給用戶組分配用戶,將用戶組與角色關聯(lián)等等...
            這些操作都是由 Administrator 來完成的.
          3. User 使用 Administrator 分配給的權限去使用各個系統(tǒng)。
          程序員只要回答一個問題,就是, 什么權限可以訪問什么資源,也就是前面說的 Operator。程序員提供 Operator 就意味著給系統(tǒng)穿上了盔甲。Administrator 就可以按照他的意愿來建立他所希望的權限框架。Operator是這個系統(tǒng)中最關鍵的部分,它是一個紐帶,一個系在Programmer,Administrator,User之間的紐帶。
          posted @ 2007-03-05 23:10 ibmsoft 閱讀(242) | 評論 (0)編輯 收藏

          http://www.pagebreeze.com/
          posted @ 2007-03-03 16:27 ibmsoft 閱讀(862) | 評論 (2)編輯 收藏

          好久沒有學習搞web開發(fā)了,最近要弄一個東西,又把appfuse找出來進行研究

          用最新的appfuse1.9.3版本!

          到:http"://appfuse.org/下載appfuse1.93

          用idea打開
          只需要修改properties.xml中的
          ????<!--?Defaults?for?database.properties?-->
          ????
          <property?name="database.jar"?location="${mysql.jar}"/>
          ????
          <property?name="database.type"?value="mysql"/>
          ????
          <property?name="database.name"?value="appfuse"/>
          ????
          <property?name="database.host"?value="localhost"/>
          ????
          <property?name="database.username"?value="root"/>
          ????
          <property?name="database.password"?value="root"/>

          把其中的localhost修改成實際的ip就ok了
          比如說是:192.169.0.1:3306,注意一定要加上端口號!

          然后在ant中運行相關的任務:
          我這里的情況是:
          建數(shù)據(jù)庫表和數(shù)據(jù)的不走是
          運行 db-prepare--》db-create--》db-load,這樣數(shù)據(jù)就建上了

          然后deploy,在ie中運行appfuse就ok了!
          posted @ 2006-08-11 16:44 ibmsoft 閱讀(411) | 評論 (0)編輯 收藏

          ?1?/*
          ?2??*?Copyright?(c)?2006?Your?Corporation.?All?Rights?Reserved.
          ?3??*/
          ?4?package?liuxuan;
          ?5?
          ?6?/**
          ?7??*?Created?by?IntelliJ?IDEA.
          ?8??*?User:?Administrator
          ?9??*?Date:?2006-7-26
          10??*?Time:?15:33:49
          11??*?To?change?this?template?use?File?|?Settings?|?File?Templates.
          12??*/
          13?import?org.htmlparser.Node;
          14?import?org.htmlparser.Parser;
          15?import?org.htmlparser.http.ConnectionManager;
          16?import?org.htmlparser.tags.LinkTag;
          17?import?org.htmlparser.util.ParserException;
          18?import?org.htmlparser.visitors.ObjectFindingVisitor;
          19?
          20?import?java.sql.Statement;
          21?import?java.sql.DriverManager;
          22?import?java.sql.Connection;
          23?import?java.sql.SQLException;
          24?
          25?public?class?LinkDemo
          26?{
          27?????public?static?void?main?(String[]?args)?throws?ParserException,?SQLException
          28?????{
          29?????????ConnectionManager?cn?=?new?ConnectionManager();
          30?????????cn.setProxyHost("10.75.1.38");
          31?????????cn.setProxyPort(80);
          32?????????Parser.setConnectionManager(cn);
          33?????????Parser?parser;
          34?????????//parser.s
          35?????????String[]?pyurl?=?new?String[2]?;
          36?
          37?????????pyurl[0]="http://www.google.cn/search?num=100&hl=zh-CN&newwindow=1&q=%E6%BF%AE%E9%98%B3&btnG=%E6%90%9C%E7%B4%A2&meta=cr%3DcountryCN";
          38?????????pyurl[1]="http://www.google.cn/search?q=%E6%BF%AE%E9%98%B3&num=100&hl=zh-CN&lr=&cr=countryCN&newwindow=1&start=100&sa=N";
          39?????????for?(int?j=0;j<pyurl.length;j++)?{
          40?????????????parser?=?new?Parser?(pyurl[j]);
          41?????????????ObjectFindingVisitor?visitor?=?new?ObjectFindingVisitor?(LinkTag.class);
          42?????????????parser.visitAllNodesWith?(visitor);
          43?????????????Node[]?links?=?visitor.getTags?();
          44?????????????String?sql;
          45?????????????????try?{
          46?????????????????????????Class.forName("com.mysql.jdbc.Driver");
          47?????????????????????}?catch?(ClassNotFoundException?e)?{
          48?????????????????????????e.printStackTrace();??//To?change?body?of?catch?statement?use?File?|?Settings?|?File?Templates.
          49?????????????????????}
          50?????????????????????Connection?conn?=?null;
          51?????????????????????try?{
          52?????????????????????????conn?=?DriverManager.getConnection("jdbc:mysql://localhost:3306/crawdb",?"root",?"root");
          53?????????????????????}?catch?(SQLException?e)?{
          54?????????????????????????e.printStackTrace();??//To?change?body?of?catch?statement?use?File?|?Settings?|?File?Templates.
          55?????????????????????}
          56??????????????Statement?stmt?=?conn.createStatement();
          57?????????????for?(int?i?=?0;?i?<?links.length;?i++)
          58?????????????{
          59?????????????????????sql="";
          60?????????????????LinkTag?linkTag?=?(LinkTag)links[i];
          61?????????????????if?(linkTag.getLink().indexOf("cache")<0?&&??linkTag.getLink().indexOf("google")<0?&&linkTag.getLinkText().indexOf("濮陽")>0)??{
          62?
          63?
          64???????????????????????sql="insert?into?urls(name,note,url)?values('"+linkTag.getLinkText?()+"','"+"lixuan"+"','"+linkTag.getLink?()+"')";
          65???????????????????????stmt.executeUpdate(sql);
          66?????????????????????????//rs.close();
          67?
          68?????????????????????System.out.print?("\""?+?linkTag.getLinkText?()?+?"\"?=>?");
          69?????????????????System.out.println?(linkTag.getLink?());
          70?????????????????}
          71?????????????}
          72??????????????stmt.close();
          73??????????????conn.close();
          74?????????}
          75?????}
          76?
          77?}
          78?

          posted @ 2006-07-25 17:26 ibmsoft 閱讀(343) | 評論 (0)編輯 收藏

          • I use nutch to crawl the intranet.but you know ,the cache.jsp have mang problem (X).Because I filter the gif|jgf and so on
            then I use ORO replace the html content use my customer pif
            Code:
            ?1????String?sRegexpSrc="src\\s*=\\s*\"([\\.]*)/([a-z]*)/([^\"]+)";
            ?2????String?sRegxpBackground?="background\\s*=\\s*\"([.]*)/([a-z]*)/([^\"]+)";
            ?3????String?sAdd?=?"";
            ?4????String?sNewContent="";
            ?5????PatternCompiler?compiler?=?new?Perl5Compiler();
            ?6????Pattern?pattern?=?null,pattern1?=?null?;
            ?7????try{
            ?8????????pattern?=?compiler.compile(sRegexpSrc,Perl5Compiler.CASE_INSENSITIVE_MASK);
            ?9????????pattern1?=?compiler.compile(sRegxpBackground,Perl5Compiler.CASE_INSENSITIVE_MASK);
            10????}
            catch?(MalformedPatternException?e){
            11????????
            12????????e.printStackTrace();
            13????}

            14????PatternMatcher?matcher?=?new?Perl5Matcher();
            15
            16if?(matcher.contains(content,?pattern)){
            17????????????????????MatchResult?result?=?matcher.getMatch();
            18????????????????????//System.out.println(result.toString());
            19????????????????????sAdd?=?result.group(1)+"/"+result.group(2)+"/"+result.group(3);
            20????????????????????//System.out.println("sAdd=?"+sAdd);
            21????????????????????sNewContent=content.replaceAll(sAdd,"\\img\\liuxuan");
            22????????????????????//System.out.println("FinalString="+sTest.replaceAll(sAdd,"/img/liuxuan.png"));
            23????????????//System.out.print("sTest=?"+result.group(1)+"/"+result.group(2));
            24????????}
            else{
            25????????????//System.out.print("Can't?find?the?String?");
            26
            27????????}

          posted @ 2006-06-28 21:03 ibmsoft 閱讀(348) | 評論 (0)編輯 收藏

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