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我們一起學網絡程序設計之四~~~~~~~~~~~~~~~~~~利用服務器與多客戶進行通信創建一個游戲

剪刀石頭布游戲
????? 在程序中約定0、1、2分別對應剪刀、石頭、布.
????? 這里還要用到套接字管理器(Vector).
???? Server4.java

import?java.net.*;

import?java.io.*;

import?java.util.*;

public?class?Server4?{

????Vector?sManager=new?Vector();

???private?ServerSocket?server;

???Random?rnd=new?Random();

????public?Server4()?{}

???void?startServer(){

???????try{

????server=new?ServerSocket(7788);

???????System.out.println("服務器套接字創建完畢");

???????while(true){

???????????Socket?socket=server.accept();

???????????System.out.println("已經與客戶機連接");

???????????new?KBBCom_Thread(socket).start();

???????????sManager.add(socket);

???????????System.out.println("當前客戶機連接數:?"+sManager.size());

????????}

???}catch(Exception?e){

???????System.out.println(e);

?????}

???}

????public?static?void?main(String[]?args)?{

????????Server4?server=new?Server4();

????????server.startServer();

????}

class?KBBCom_Thread?extends?Thread{

????Socket?socket;

????private?DataInputStream?reader;

????private?DataOutputStream?writer;

????KBBCom_Thread(Socket?socket){

????????this.socket=socket;

????}

????public?void?run(){

????????try{

????????

????????reader=new?DataInputStream(socket.getInputStream());

????????writer=new?DataOutputStream(socket.getOutputStream());

????????String?msg;

????????while((msg=reader.readUTF())!=null){

????????????if(msg.equals("OK"))

????????????????writer.writeInt(rnd.nextInt(3));

????????????????writer.flush();

????????}

????}catch(Exception?e){

????}finally{

????????try{

????????????sManager.remove(socket);

????????????if(reader!=null)?reader.close();

????????????if(writer!=null)?writer.close();

????????????if(socket!=null)?socket.close();

????????????reader=null;?writer=null;?socket=null;

????????????System.out.println("客戶機離開");

????????????System.out.println("當前客戶機連接數:?"+sManager.size());

????????}catch(Exception?e){}

????}

??}

}

Client4.java

import?java.awt.*;

import?java.net.*;

import?java.io.*;

import?java.awt.event.*;

public?class?Client4?extends?Frame?implements?ActionListener{

????private?TextArea?msgView=new?TextArea();

????private?Button?b1,b2,b3;

????private?DataInputStream?reader;

????private?DataOutputStream?writer;

????public?static?int?B1=0;

????public?static?int?B2=1;

????public?static?int?B3=2;

????Socket?socket;

????public?Client4(String?title)?{

????????super(title);

????????msgView.setEditable(false);

????????b1=new?Button("剪刀");

????????b2=new?Button("石頭");

????????b3=new?Button("布");

????????add(msgView,"Center");

????????Panel?p=new?Panel();

????????p.add(b1);?p.add(b2);?p.add(b3);

????????add(p,"South");

????????b1.addActionListener(this);

????????b2.addActionListener(this);

????????b3.addActionListener(this);

????????pack();

????}

????

????private?void?connect(){

????????try{

????????????msgView.append("嘗試與服務器連接\n");

????????????socket=new?Socket("192.168.1.22",7788);

????????????msgView.append("開始游戲\n");

????????????reader=new?DataInputStream(socket.getInputStream());

????????????writer=new?DataOutputStream(socket.getOutputStream());

????????}catch(Exception?e){

????????????msgView.append("連接失敗");

????????}

????}

????public?void?actionPerformed(ActionEvent?ae){

????????int?player=-1,server=-1;

????????if(ae.getSource()==b1)?player=B1;

????????else?if(ae.getSource()==b2)?player=B2;

????????else?if(ae.getSource()==b3)?player=B3;

????????if(player==-1)?return;

????????try{

????????????writer.writeUTF("OK");

????????????writer.flush();

????????????server=reader.readInt();

????????}catch(IOException?ie){}

????????if(player==server)?msgView.append("平局\n");

????????else?if(player>server||player-server==2)?msgView.append("獲勝\n");

????????else?msgView.append("失敗\n");

????}

????public?static?void?main(String[]?args)?{

???????Client4?client=new?Client4("剪刀石頭布游戲");

???????client.setVisible(true);

???????client.connect();

????}

}

posted on 2007-05-12 13:03 逍遙客閱讀(321) 評論(0) 編輯收藏

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我們一起學網絡程序設計之四~~~~~~~~~~~~~~~~~~利用服務器與多客戶進行通信創建一個游戲