b47617

要求：斯諾克臺球共有21個球,其中有15個紅色一分球，另有其它顏色的2,3,4,5,6,7分球各一個，規(guī)則是先打一個紅色球，然后可以打一個其他分值的球，如此反復(fù)，如果臺面還有紅色球，打入的高分球計分，同時拿出來放回原位置，當打入最后一個紅球后再去打其它色球時,那個色球同樣要拿出來放回原位,接著按照分數(shù)由低到高,分別將2到7分的各色球打盡.要求寫一段簡單的java函數(shù)，實現(xiàn)輸入臺面上剩余球的數(shù)目，計算出可得的最高分。（不考慮罰分等特殊情況）
作算術(shù)分析:每打一個紅球和一個色球能得到的最高分值是1+7=8分,全部紅球打盡所得最高分值:15*8=120分,再加上其它色球的總分值:120+2+3+4+5+6+7=147分.至于怎么樣實現(xiàn)輸入球數(shù)就能得到最高分值嘛,
public class CountMaxScore{
               public int CountMaxScore(int ballnum){//計算最高得分
                              int max = 0;                          //
                              int ball = ballnum;                  //ballnum 傳入的剩下的球數(shù)．
                              if(ball <= 6){                        //
                                     max = (21 - ball) * 8;
                                     return max;
                              }else{
                                 max  = 15 * 8;
                                 if(int i = 2;i <= (7-ball);i++){
                                             max = max + i;
                                 }
                                    return max;
                                }
               }
              static public void main(String[] args){
                        CountMaxScore　msc  = new CountMaxScore();
                         BufferReader in = new BufferReader(new InputStreamReader(System.in));
                           try{
                                 String s = in.ReadLine();
                                 int ball = Integer.parseInt(s);
                                 maxscor = msc.CountMaxScore(ball);
                                 System.out.println("桌面上剩下"+ball+"個球時，選手的最高得分可達："+maxscore+"分");
                                 }catch(Exception e){}
               }
}