alex-0927 — Mon, 23 Apr 2007 11:39:00 GMT

通过一个integer�c�d��属性来表示对象所处的状态：

CASE:
Invitor:邀误��对象模�?br />Integer Invitor.joinstatus:邀误��所处参加状�?br />当前存在状态声明：是否被邀��P��是否注册用户�Q�是否拒�l�，是否审批

设计思�\�Q?br />bit0: 1-invited , 0-not invited
bit1: 1-registed , 0-not registed
bit2: 1-refused , 0-not refused
bit3: 1-approved , 0-not approved

Example:0111(7)=the invitor is invited ,and is registed ,and has been refused without approved.

//判断joinstatus状�?br />public static String theStatusOfApplicant(Invitor iv) throws TrainingAppException {
  String status = "default";
  if (((iv.getJoinStatus() & 0x8) == 0) && ((iv.getJoinStatus() & 0x4) == 0)) {
   status = "default";// 待批�?0x0)
  }
  if (((iv.getJoinStatus() & 0x8) == 0x8) && ((iv.getJoinStatus() & 0x4) == 0)) {
   status = "approved";// 已审�?0x4)
  }
  if (((iv.getJoinStatus() & 0x4) > 0) && ((iv.getJoinStatus() & 0x8) == 0)) {
   status = "refused";// 已拒�l?0x8)
  }
  return status;
}
//更新joinstatus状�?审批和拒�l��ؓ互斥)
private void updateJoinstatus(MainTrainingInfo mtrInfo, List invitors, Integer opertorType) {
  for (Iterator it = invitors.iterator(); it.hasNext();) {
   Invitor iv = (Invitor) it.next();
   if (APPLY_OPERTORTYPE_APPROVE == opertorType.intValue()) { // approve
    iv.setJoinStatus((iv.getJoinStatus() | 0x8) & 0x8);
   } else {
    iv.setJoinStatus((iv.getJoinStatus() | 0x4) & 0x4); // refuse
   }
   iv.setMainId(mtrInfo);
   mtrInfo.getInvitor().add(iv);
  }

  persistence.update(mtrInfo);
  if (APPLY_OPERTORTYPE_APPROVE == opertorType.intValue()) { // approve
   log.info(" ### 甌��已获批准,发送邀请邮�?");
   // Send Mails.
   try {
    instanceMailSendService.approveInvitorSendMail(mtrInfo, invitors, getHostEmail(mtrInfo),
      MainTrainingInfoUtil.getLocale(mtrInfo), true, true);
   } catch (Exception e) {
    log.error(e.toString());
   }

}
}

alex-0927 2007-04-23 19:39 发表评论

Hibernate Native SQL Support

alex-0927 — Mon, 16 Apr 2007 11:36:00 GMT

1.使用SQLQuery

对原生SQL查询执行的控制是通过SQLQuery接口�q�行的，通过执行Session.createSQLQuery()获取�q�个接口。最��单的情况下，
可以采用以下形式�Q?/font>

List cats = sess.createSQLQuery("select * from cats")
.addEntity(Cat.class)
.list();
�q�个查询指定�?

SQL查询字符�?/font>

查询�q�回的实�?/font>

�q�里�Q�结果集字段名被假设��Z��映射文�g中指明的字段名相同。对于连接了多个表的查询�Q�这��可能造成问题�Q�因为可能在�?br />个表中出现同样名字的字段。下面的�Ҏ��可以避免字�D�名重复的问�?

List cats = sess.createSQLQuery("select {cat.*} from cats cat")
.addEntity("cat", Cat.class)
.list();
�q�个查询指定�?

SQL查询语句�Q�它带一个占位符�Q�可以让Hibernate使用字段的别�?

查询�q�回的实体，和它的SQL表的别名.

addEntity()�Ҏ��SQL表的别名和实体类联系��h��Q��ƈ且确定查询结果集的�Ş态�?

addJoin()�Ҏ��可以被用于蝲入其他的实体和集合的兌��.

List cats = sess.createSQLQuery(
"select {cat.*}, {kitten.*} from cats cat, cats kitten where kitten.mother = cat.id"
)
.addEntity("cat", Cat.class)
.addJoin("kitten", "cat.kittens")
.list();
原生的SQL查询可能�q�回一个简单的标量值或者一个标量和实体的结合体�?

Double max = (Double) sess.createSQLQuery("select max(cat.weight) as maxWeight from cats cat")
.addScalar("maxWeight", Hibernate.DOUBLE);
.uniqueResult();
除此之外�Q�你�q�可以在你的hbm文�g中描�q�结果集映射信息�Q�在查询中��用�?/font>

List cats = sess.createSQLQuery(
"select {cat.*}, {kitten.*} from cats cat, cats kitten where kitten.mother = cat.id"
)
.setResultSetMapping("catAndKitten")
.list();

2.命名SQL查询

可以在映��文档中定义查询的名�?可以象调用一个命名的HQL查询一��L��接调用命名SQL查询.在这�U�情况下,不需要调用addEntity()
�Ҏ��.

SELECT person.NAME AS {person.name},
person.AGE AS {person.age},
person.SEX AS {person.sex}
FROM PERSON person
WHERE person.NAME LIKE :namePattern

List people = sess.getNamedQuery("persons")
.setString("namePattern", namePattern)
.setMaxResults(50)
.list();

在sping里面用回调查�?br />    public List getPaysByBizId(final String bizId) {
    return (List)getHibernateTemplate().execute(new HibernateCallback(){
    public Object doInHibernate(Session session)throws HibernateException{
    Query query = session.getNamedQuery("find.pays.by.bizid");
    query.setParameter("bizId",bizId);
    return query.list();
    }
    },true);
    }

alex-0927 2007-04-16 19:36 发表评论

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Hibernate Native SQL Support