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select集連+xml+選擇提交 (Ajax局部刷新)

摘要: Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> 1?<rows><row?id='1703'?name='武昌南機務段????'?/><row?id='1701'?name='襄樊北機務段????'?/>... 閱讀全文

posted @ 2007-07-02 10:22 G_G 閱讀(3066) | 評論 (2) | 編輯收藏

問題 : 提供給B/S 結構一個實時的運行展現
解決:?? prototype 的?Ajax.PeriodicalUpdater 更新
??????????? prototype 的??? Ajax.Request 語句提交
????????????action 語句的組織展現

http://www.aygfsteel.com/Files/Good-Game/take.rar
????沒有lib 大家可以就加 struct 相關 lib 就可以了

說明:?
??????

<!DOCTYPE?HTML?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN">

<html>

??<head>

??????????<SCRIPT?language="Javascript"?src="prototype1.5.0.js"></SCRIPT>

??</head>

??

??<body?onload="Said()">?

??????<INPUT?id='name1'?type="text"?size="10"?value="請輸入名字"?onfocus="if($('name1').value=='請輸入名字')?$('name1').innerText=''?"?/>

??????<INPUT?id='text1'?type="text"?onkeydown="if(event.keyCode==13){event.keyCode=0;?onb();}"/>

??????<INPUT?id='button1'?type="button"?value="test"?onclick='onb()'?/>

??</body>

??<div?id='div1'/>

</html>

??????? //語句異步提交給服務器 Ajax.Request

????function?onb(){?????????????????????????????????????????

??????if($('name1').value=='請輸入名字'?||?$('name1').value==''){

??????????window.alert('請輸入名字');

??????????return?

??????}

??????

??????var?url?=?'http://192.168.1.130:7000/xxs/mySaid.do?name='+$F('name1')+'&take='+$F('text1');????????????????

??????new?Ajax.Request(

????????url,

????????{

????????????method:?'get',

????????????onComplete:?action??????????????

????????});

????????

????????$('name1').readOnly?=?true

????????$('name1').style.background?=?'lightblue'

????????$('text1').innerText=''?

????}

?????? //局部刷新并提取語句

????function?Said(){

????????var?url?=?'http://192.168.1.130:7000/xxs/mySaid.do';??

????????new?Ajax.PeriodicalUpdater(

????????????'div1',

????????????url,

????????????{

????????????????method:?'get',

????????????????onComplete:?SumSaid,

????????????????evalScripts:?true,

????????????????frequency:?1,

????????????????decay:?1

????????????}

????????);

????}

?????? //展現

????function?SumSaid(req){

????????$('div1').innerHTML?=?req.responseText;

????}

????function?action(req){

????}

????</script>

????

Action

?? private static int SIZE = 30 ;
???? private List list = new ArrayList();

???? public?ActionForward?execute(

????????ActionMapping?mapping,

????????ActionForm?form,

????????HttpServletRequest?request,

????????HttpServletResponse?response)?{

????????String?take?=?request.getParameter("take")?;

????????String?name?=?request.getParameter("name")?;

????????response.addHeader("Cache-Control","no-cache");?

????????

????????request.setAttribute("said",DueiLie(name,take));

????????try?{

????????????request.setCharacterEncoding("gb2312");

????????????response.setCharacterEncoding("gb2312");

????????}?catch?(Exception?e)?{

????????}

????????return?mapping.findForward("list");

????}

?????
??????? //語句的組織

????public?String?DueiLie(String?name,String?take){

????????

????????StringBuffer?strb??=?new?StringBuffer();

????????if(name==null||take==null);

????????else{

????????????strb.append(?name?).append("?:?").append(take).append("</br>")?;

????????????if(list.size()==SIZE){

????????????????list.remove(list.get(0));

????????????????list.add(strb.toString()?);

????????????}else{

????????????????list.add(?strb.toString()?);

????????????}

????????}

????????StringBuffer?takes?=?new?StringBuffer();

????????Iterator?it?=?list.iterator();

????????while(it.hasNext()){

????????????takes.insert(?0,(String)it.next()?);

????????}

????????return?takes.toString();

????}

jsp ( list ) 中文處理 jsp 就一句話
<%= new String(((String)request.getAttribute("said")).getBytes("iso8859-1"),"GBK") %>

心得:別人做到了我也能做到
?????????要學的東西很多多看書多留意多保護好身體

posted @ 2007-06-13 10:22 G_G 閱讀(1453) | 評論 (3) | 編輯收藏

HTML 中 select 選擇

???? function ?selectValue(select,val) {

???????? var ?opt? = ?select.options?;

???????????????? for ( var ?i = 0 ;i < opt.length;i ++ ) {

???????????? if (?opt[i].firstChild.nodeValue? == ?val) {

????????????????opt[i].selected? = ? true ;

???????????????? return ?;?

????????????}

????????}

???????? for ( var ?i = 0 ;i < opt.length;i ++ ) {

???????????? if (?opt[i].value? == ?val) {

????????????????opt[i].selected? = ? true ;

???????????????? return ?;?

????????????}

????????}

????}

????

posted @ 2007-06-12 16:29 G_G 閱讀(402) | 評論 (0) | 編輯收藏

java報表 Cell50

問題:???? 對數據的打印
解決:???? 用友華表Cell插件與IE 結合?
???????????????在jsp 中用包裝好的標簽來實現數據展現?

???Cell下載(http://mail.google.com/mail/?realattid=f_f2smalft&attid=0.1&disp=attd&view=att&th=11319ae8ff5275c3)后改成*.zip

簡單例題下載? http://www.aygfsteel.com/Files/Good-Game/paobiao.rar?????????? 解壓為 war 后就直接 http://localhost:7000/paobiao/paobiao.do

大家要是會 ec 那就簡單了 <jjmtabletag:exttable>標簽包裝的和 ec 很想??
先用報表軟件畫個樣式我的是??? form/Tat.cll
后在 jsp 中

<% @?page?language = " java " ?pageEncoding = " UTF-8 " %>

<% @?taglib?prefix = " ajax " ?uri = " /WEB-INF/ajaxtags.tld " ? %>

<% @?taglib?uri = " http://www.jjm.cn/tags-tables " ?prefix = " jjmtabletag " %>

<! DOCTYPE?HTML?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN" >

< html > ?

???? < head >

???????? < title > JSP?for?paobiaoForm?form </ title >

???????? < script? type ="text/javascript" ?src ="<%=request.getContextPath()%>/js/jjmtag.js" ></ script > ???

???? </ head >

?????? < body? onload ="window_onload()" >

????

?????? < jjmtabletag:exttable

?????????? templateFile ="/form/Tat.cll" ????????????????????????? //報表的格式的所在地

??????????action ="/paobiao.do" ?

??????????firstRow ="3" ?????????????????????????????????????????????????????????????????????????????????????//從第3行開始

??????????primaryKey ="name" ????????????????????????????????????????????????????????????????????????????????????

??????????items ="list" ????????????????????????????????????????????????????????????????????????????????????????????????????

??????????searchButtonVisible ="false"?????????????????????????????????????????????????????????????????????

??????????ajaxEnabled ="false" >???
???????????? ?<jjmtabletag:column col="2" row="5" property="" value='liukaiyi' />?? //在?第5 行第2??列 'liukaiyi'可以<%= ....%>

??????????<jjmtabletag:column?col="1"?property="name"/>???????????????????????//讀集合 list 中(循環)的元素并從第三行開始

??????</jjmtabletag:exttable>???

????</body>

</html>

其他的大家看看吧簡單剛到公司發現這個很好消化下就貼出來(時間問題例題不好)
歡迎大家評論

posted @ 2007-06-12 10:23 G_G 閱讀(1159) | 評論 (2) | 編輯收藏

動態建表(2) bean[] 直接到建表 (擴展也很好)

摘要: 問題: 提供簡單 java 和 javascript API?解決: 對 hbm 得到的 bean[] 自動生成 xml??? public void addXml(String tableName,String idName,Object[] bean){??????????????????????????????????????????????????格式 <tableName&g... 閱讀全文

posted @ 2007-06-06 17:29 G_G 閱讀(1313) | 評論 (0) | 編輯收藏

用javascript 建 tree

問題： 總是用別人的框架寫樹以為很難，其實。。。
解決：以 if event.srcElement.id=="foldheader1" 得到選項
???? ??? var srcIndex = event.srcElement.sourceIndex
??? ?? ? 再 var nested = document.all[srcIndex+1] 取出選擇的下一個 ( +1 )
??? ?? ?? ??? nested.style.display=' ？？ ' 就可以了
??? ?? ?? ?? 并注意結構是
??? ?? ?? ?? ?? ?? ?? ?? <選項/>??
??? ?? ?? ?? ?? ?? ?? ?? ?? <url>??//srcIndex+1 下個可見不可見就是 <url>
??? ?? ?? ?? ?? ?? ?? ?? ?? ?? <li>...</li>
??? ?? ?? ?? ?? ?? ?? ?? ?? ??? <li>...</li>
??? ?? ?? ?? ?? ?? ?? ?? ?? ?? ? ....
??? ??? ??? ??? ??? ??? ??? </url>

<HEAD>

????<SCRIPT?language=JavaScript1.2>
????function?change(){
???????if(!document.all)
??????????return
???????if?(event.srcElement.id=="foldheader1")?{
??????????var?srcIndex?=?event.srcElement.sourceIndex
??????????
??????????var?nested?=?document.all[srcIndex+1]

??????????if?(nested.style.display=="none")?{
?????????????nested.style.display=''
??????????}
??????????else?{
?????????????nested.style.display="none"
??????????}
???????}
????}
????</SCRIPT>

????<STYLE>
????????#foldheader1?{????? 
????????????CURSOR:?hand;?LIST-STYLE:?url(../rlzy/images/imbrex.gif)?
????????}
????</STYLE>
</HEAD>
<BODY?leftMargin=0?rightMargin=0?onload="window.status='';">
??<font?size="-1">

<DIV?id="Layer2"?style="HEIGHT:?134px;?LEFT:?2px;?POSITION:?absolute;?TOP:?30px;?WIDTH:?193px;?Z-INDEX:?3">
??<UL?style="MARGIN-LEFT:?20px">?
????????
????????
????????
????????<li>
??????????<a?href="#"?onClick="change()"?id="foldheader1">乘務員基本檔案</a>
??????????<ul?id=foldinglist?style="''"?style="MARGIN-LEFT:?10px">
????????????<li><a?href="/rlzy/jcyy/basePersonnelList.do?do=byCorp"?target="content">人員基本檔案1</a></li>
????????????<li><a?href=""?target="content">人員基本檔案2</a></li>
??????????</ul>
????????</li>
????????
??????</UL>
????</DIV>????????
??</font>
</BODY>
</html>

<FRAMESET?rows="84,*"?cols="*"?frameborder="no"?framespacing="0"?border="0">
??<FRAME?src="header.html"?name="header"?scrolling="no">
??<FRAMESET?cols="125,*"?frameborder="no"?framespacing="0"?border="0">
????<FRAME?name="treefrm"?src="dir2.jsp?code=0"?scrolling="no">
????<FRAME?name="content"?src="welcome.jsp">
??</FRAMESET>

心得：其實很簡單，只是你不知道

posted @ 2007-06-06 11:01 G_G 閱讀(811) | 評論 (2) | 編輯收藏

解讀String 來進行對象與對象之間的操作的

????????ApplicationContext?app? = ? new ?FileSystemXmlApplicationContext( " analysis.xml " );
????????AnalysisFactory?af? = ? new ?AnalysisFactoryImp();
????????
????????test?tt? = ? new ?test();
????????
????af.setOrder( " ?:$2:?:$0:fr=f5%8?:$1:name? " ?,? new ?Object[] { " liu " ,tt, " heha " } );??
?????????????????????????//每個對象以空格分開?每個有范圍:?對象名?: 對自己的操作?????
?????????????????????????//例如 analysis:test:???就是重 spring?中得到?????test 對象
????????????????????????//關鍵所在以String 代替簡單邏輯 API? 就很一致并接近自然語言
????????af.submits();
????????System.out.println(?((test)af.getAttribure( " $1 " )).getName()?);

????????
問題: 對眾多API我們能怎么樣呢?
解決:用String 再提供一個對象得到你想要的

下載:
?http://www.aygfsteel.com/Files/Good-Game/MyUtil.rar
??????首先 .classpath 文件配置 CLASSPATH
???????文件 src 源文件 /test-----
?????????????????????????????????????????????/bean/test.java????? 為使用test Bean
?????????????????????????????????????????????/TestFactory.java? 為測試
???????????????????????????????????/analysis-------
?????????????????????????????????????????????/AnalysisFactory.java? 為interface方向類
?????????????????????????????????????????????/imp------
???????????????????????????????????????????????????/AnalysisFactoryAbs.java??為抽象類
???????????????????????????????????????????????????/AnalysisFactoryImp.java???為類

在AnalysisFactoryImp.java???中
????????protected Object action(List ele)?????ele? 內一行 name , object , logic , size 為存取?
????????????????????????????????????類與類之間的動作??
????????protected boolean isScopeExpansion(List vs, String scope, String className)
?????????????????????????????????????類的初次完成用vs.set(1, -對象- ?); 填充
????????protected boolean isInSetExpansion(String inOp, Object object)
??????? protected void inAction(List vs)

心得: 寫的不好但想法就是以String 提供統一的簡單的API ??

posted @ 2007-06-05 09:51 G_G 閱讀(802) | 評論 (0) | 編輯收藏

ajax 對 struct 異步提交標簽的解決辦法

問題: ? struct 標簽沒有直接與ajax 數據兼容互換方法
解決: 先用struct 動態得到數據?,再利用javascrpit 的 function(this) 把值提取交給 ajax

需要提交的 struct link 項

<div1/>

js 控制

????????????function?action(obj){

????????????????var?str?=?obj.getAttribute('href');??????????????????

????????????????var?id?=?str.substring(?str.lastIndexOf('=')+1,?str.length?);?????????// 取得 href 中的的值 (由 struct 得到的動態值?)

???????????????????var?pars?=?'do=edit&personnelId='+id;

????????????????new?Ajax.Updater('div1','/rlzy/jcyy/basePersonnelList.do?',{parameters:pars,valScripts:true}); //由 prototype 的 ajax 異步提交

????????????????Element.hide(document.getElementById("div2"));

????????????????Element.show(document.getElementById("div1"));

????????????????

????????????????return?false;

????????????}

????????????function?action2(){

????????????????Element.hide(document.getElementById("div1"));

????????????????Element.show(document.getElementById("div2"));

????????????}

????????</SCRIPT>

rlzy/jcyy/basePersonnelList.do? 的頁面? 就局部加入頁面 div1 了
<INPUT type='button' value="test" onclick="action2();"/>

感想:? javascript 萬能膠水

posted @ 2007-05-25 18:44 G_G 閱讀(823) | 評論 (0) | 編輯收藏

XMLDOM 詳細說明和網上有關資源 + 動態javascript建表

問題: 對javascript Dom 解讀 xml? 的問題
解決: 網頁中 javascript 學習

過程 js

function?searchSales(){

????var?url?=?"MyXml.xml";???????????// url 不限制可以為 jsp? *.do? 只要 out.print()出來的是 xml 格式

????var?myAjax?=?new?Ajax.Request(

???????????? ?url,

????{

????method:?'get',

????onComplete:?action????????????? // 成功得到 requ 的掛載方法

????});

}

function??action(request)

{

????var?dom?=?request.responseXML;??? //返回 javascript Dom 解讀對象

????

????var?list?=?dom.getElementsByTagName('Weapon');?

????????????????????????????????//返回標簽名<Weapon>? 集合項可用.item(i) 得出? .firstChild.nodeValue得值

?

????for(?var?i?=?0;?i?<?list.length;?i++?)?{

????????var?nli?=?list.item(i);

????????var?W?=?nli.getElementsByTagName(?'W'?);

????????window.alert(W.item(0).firstChild.nodeValue);

????}

?????

}

HTML 頁面

</HEAD>

<head>

????<script?src="prototype1.5.0.js"></script>

????<script?src="xml.js"></script>

</head>

<input?id='test'?type="submit"?value="test"?onclick="searchSales();"?>

</HTML>

XML

<?xml?version="1.0"?encoding="utf-8"??>

<Login>

????<Weapon?id="1">

????????<W?Text="光束劍"?Value="0">1</W>

????????<W?Text="光束配刀"?Value="1">2</W>

????</Weapon>

????<Weapon?id="2">

????????<W?Text="光束劍"?Value="0">3</W>

????????<W?Text="光束配刀"?Value="1">4</W>

????</Weapon>

????

?????<Weapon?id="3">

????????<W?Text="光束劍"?Value="0">5</W>

????????<W?Text="光束配刀"?Value="1">6</W>

????</Weapon>

</Login>

心得: 調試了很久當時對javascript 的不熟悉,但我沒有放棄去網上查,問同事最后成功
?????????????????---------------------?堅持就是勝利?------------------

posted @ 2007-05-18 17:33 G_G 閱讀(1011) | 評論 (5) | 編輯收藏

html 簡單 div 拖動

問題:? 興趣
解決:?? div的 onclike ( this?)? 得到選擇?
????????????由 window.event 得到鼠標 x y?
????????????由 this.style.top/left 改變 div 位置?

????????var?x,y;
????????function?mousedown(obj)
????????{
????????????obj.onmousemove?=?mousemove;
????????????obj.onmouseup?=?mouseup;
????????????
????????????oEvent?=?window.event???window.event?:?event;
????????????x?=?oEvent.clientX;
????????????y?=?oEvent.clientY;
????????}
????????function?mousemove()
????????{
????????????oEvent?=?window.event???window.event?:?event;
????????????var?_top?=?oEvent.clientY?-?y?+?parseInt(this.style.top)?+?"px"; // oEvent.clientY?-?y? 為div 上移動的位置再反映到 ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ?? //parseInt(this.style.top)
????????????var?_left?=?oEvent.clientX?-?x?+?parseInt(this.style.left)?+"px";
????????????this.style.top?=?_top;
????????????this.style.left?=?_left;
????????????x?=??oEvent.clientX;
????????????y?=??oEvent.clientY
????????}
????????function?mouseup()
????????{
????????????this.onmousemove?=?null;
????????????this.onmouseup?=?null;
????????}

心得: 興趣決定一切

posted @ 2007-05-08 12:28 G_G 閱讀(3898) | 評論 (5) | 編輯收藏

Skynet

select集連+xml+選擇提交 (Ajax局部刷新)

頁面嵌入在線聊天 (prototype)

HTML 中 select 選擇

java報表 Cell50

動態建表(2) bean[] 直接到建表 (擴展也很好)

用javascript 建 tree

解讀String 來進行對象與對象之間的操作的

ajax 對 struct 異步提交標簽的解決辦法

XMLDOM 詳細說明和網上有關資源 + 動態javascript建表

html 簡單 div 拖動

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