扩展è¯ïL§»æ¥ç¼–½E‹ç»ƒä¹?åQ?/span>
#include <stdio.h>
void to_binary(unsigned long n);
int main(void)
{
unsigned long number;
printf("Enter an integer (q to quit): \n");
while(scanf("%lu", &number) == 1)
{
printf("Binary equivalent: ");
to_binary(number);
putchar('\n');
printf("Enter an integer (q to quit): \n");
}
printf("Done!\n");
return 0;
}
void to_binary(unsigned long n)
{
int r;
r = n % 2;
if(n >= 2)
to_binary(n / 2);
putchar('0' + r);
return;
}
å¤ä¹ é¢?/span>
1ã€å®žé™…傿•°å’Œå½¢å¼å‚釿œ‰ä½•ä¸åŒåQ?br />½{”:
å½¢å¼å‚é‡åQˆä¹Ÿè¢«ç§°ä¸ºåÅžå¼å‚敎ͼ‰æ˜¯ä¸€ä¸ªå˜é‡ï¼Œå®ƒåœ¨è¢«è°ƒå‡½æ•°ä¸è¿›è¡Œå®šä¹‰ã€‚å®žé™…å‚æ•°æ˜¯åœ¨å‡½æ•°è°ƒç”¨ä¸å‡ºçŽ°çš„å€û|¼Œå®ƒè¢«èµ‹å€¼ç»™å½¢å¼å‚é‡ã€‚å¯ä»¥æŠŠå®žé™…傿•°è®¤äؓ是在函数被调用时用æ¥åˆå§‹åŒ–åÅžå¼å‚é‡çš„倹{€?br />2ã€å†™å‡ÞZ¸‹é¢æ‰€æè¿°çš„å„个函数的ANSI函数头。注æ„:åªå†™å‡ºå‡½æ•°å¤´å›_¯åQŒä¸éœ€è¦å®žçްã€?br />a.donut()接å—一个int¾cÕdž‹çš„傿•ŽÍ¼Œç„¶åŽè¾“出若干ä¸?åQŒè¾“å‡?的数目ç‰äºŽå‚数的倹{€?br />b.gear()接å—两个int¾cÕdž‹çš„傿•°åƈ˜q”回int¾cÕdž‹çš„倹{€?br />c.stuff_it()çš„å‚æ•°åŒ…括一个double¾cÕdž‹çš„å€ég»¥åŠä¸€ä¸ªdouble¾cÕdž‹å˜é‡çš„地å€åQŒåŠŸèƒ½æ˜¯æŠŠç¬¬ä¸€ä¸ªæ•°å€¼å˜æ”‘Öˆ°æŒ‡å®šçš„地å€ä¸ã€?br />½{”:
a.void donut(int n)
b.int gear(int n, int m)
c.void stuff_it(double n, double * d)
3ã€åªå†™å‡ºä¸‹åˆ—函数的ANSI C函数å¤ß_¼Œä¸éœ€è¦å®žçŽ°å‡½æ•°ã€?br />a.n_to_char()接å—一个int¾cÕdž‹çš„傿•°åƈ˜q”回一个char¾cÕdž‹çš„倹{€?br />b.digits()接å—çš„å‚æ•°æ˜¯ä¸€ä¸ªdouble¾cÕdž‹çš„æ•°å€¼å’Œä¸€ä¸ªint¾cÕdž‹çš„æ•°å€û|¼Œ˜q”回值类型是intã€?br />c.random()䏿ޥå—傿•ŽÍ¼Œ˜q”回int¾cÕdž‹çš„æ•°å€¹{€?br />½{”:
a.char n_to_char(int n)
b.int digits(double n, int m)
c.int random(void)
4ã€è®¾è®¡ä¸€ä¸ªå®žçŽîC¸¤æ•´æ•°ç›¸åŠ òq¶å°†¾l“æžœ˜q”回的函数ã€?br />½{”:
int plus(int n, int m)
{
return n + m;
}
5ã€å‡å¦‚é—®é¢?ä¸çš„函数实现两个double¾cÕdž‹çš„æ•°å€¼ç›¸åŠ ï¼Œé‚£ä¹ˆåº”è¯¥å¦‚ä½•ä¿®æ”¹åŽŸå‡½æ•ŽÍ¼Ÿ
½{”:
double plus(double n, double m)
{
return n + m;
}
6ã€è®¾è®¡å‡½æ•°alter()åQŒå…¶è¾“入傿•°æ˜¯ä¸¤ä¸ªint¾cÕdž‹çš„å˜é‡xå’ŒyåQŒåŠŸèƒ½æ˜¯åˆ†åˆ«ž®†è¿™ä¸¤ä¸ªå˜é‡çš„æ•°å€¼æ”¹ä¸ºå®ƒä»¬çš„和以åŠå®ƒä»¬çš„å·®ã€?br />½{”:åQ?span style="background-color: yellow;">注æ„åQšä¸‹é¢è¿™¿U写法是错误的ï¼åQï¼åQ?/span>
void alter(int x, int y)
{
x = x + y;
y = x - y;
}
æ£ç¡®çš„写法如下:
void alter(int * u, int * v)
{
int temp;
temp = *u;
*u = *u + *v;
*v = temp - *v;
}
7ã€åˆ¤æ–下é¢çš„å‡½æ•°å®šä¹‰æ˜¯å¦æ£ç¡®ã€?br />void salami(num)
{
int num, count;
for(count = 1; count <= num; num++)
printf("O salami mio!\n");
}
½{”:
有错误。num应该在salami()çš„å‚æ•°åˆ—表ä¸è€Œä¸æ˜¯åœ¨èŠ±æ‹¬å·ä¹‹åŽå£°æ˜Žï¼Œè€Œä¸”应该是count++è€Œä¸æ˜¯num++ã€?br />8ã€ç¼–写一个函敎ͼŒä½¿å…¶˜q”回3ä¸ªæ•´æ•°å‚æ•îC¸çš„æœ€å¤§å€¹{€?br />½{”:
int max(int x, int y, int z)
{
int max;
if(x > y)
if(x > z)
max = x;
else
max = z;
else
if(y > z)
max = y;
else
max = z;
return max;
}
or åQ?span style="background-color: yellow;">更简‹z一点)
int max(int x, int y, int z)
{
int max = x;
if(y > max)
max = y;
if(z > max)
max = z;
return max;
}
9ã€ç»™å®šä¸‹é¢çš„输出åQ?br />Please choose one of the following:
1)copy files 2)move files
3)remove files 4)quit
Enter the number of your choice:
a.用一个函数实现èœå•的昄¡¤ºåQŒä¸”该èœå•有4个用数嗾~–å·çš„选项òq¶è¦æ±‚ä½ é€‰æ‹©å…¶ä¸ä¹‹ä¸€åQˆè¾“å‡ºåº”è¯¥å¦‚é¢˜ä¸æ‰€½Cºï¼‰ã€?br />b.¾~–写一个函敎ͼŒè¯¥å‡½æ•°æŽ¥å—两个int¾cÕdž‹çš„傿•ŽÍ¼šä¸€ä¸ªä¸Šç•Œå’Œä¸€ä¸ªä¸‹ç•Œã€‚在函数ä¸ï¼Œé¦–先从输入终端读å–一个整敎ͼŒå¦‚果该整æ•îC¸åœ¨ä¸Šä¸‹ç•Œè§„定的范围内åQŒåˆ™å‡½æ•°é‡æ–°æ˜„¡¤ºèœå•åQˆä‹É用本题目a部分ä¸çš„函数åQ‰ä»¥å†æ¬¡æé†’用户输入新倹{€‚如果输入数值在规定的范围内åQŒé‚£ä¹ˆå‡½æ•°åº”è¯¥å°†æ•°å€ÆD¿”回给调用函数ã€?br />c.使用本题目aå’Œb部分ä¸çš„函数¾~–写一个最ž®çš„½E‹åºã€‚最ž®çš„æ„æ€æ˜¯è¯¥ç¨‹åºä¸éœ€è¦å®žçްèœå•䏿‰€æè¿°çš„功能;它åªéœ€è¦æ˜¾½Cø™¿™äº›é€‰é¡¹òq¶èƒ½èŽ·å–æ£ç¡®çš„å“应å³å¯ã€?br />½{”:åQˆå‚考课åŽç”案)
#include <stdio.h>
void menu(void);
int get_input(int, int);
int main(void)
{
int res;
menu();
while((res = get_input(1, 4)) != 4)
printf("I like choice %d.\n", res);
printf("Bye!\n");
return 0;
}
void menu(void)
{
printf("Please choose one of the following: \n");
printf("1)copy files 2)move files\n");
printf("3)remove files 4)quit\n");
printf("Enter the number of your choice: \n");
}
int get_input(int min, int max)
{
int number;
scanf("%d", &number);
while(number < min || number > max)
{
printf("%d is not a valid choice; try again.\n", number);
menu();
scanf("%d", &number);
}
return number;
}
¾~–程¾lƒä¹
1�br />#include <stdio.h>
double min(double, double);
int main(void)
{
printf("One of the smaller of the two numbers is %.2f", min(23.34, 12.11));
return 0;
}
double min(double x, double y)
{
return x < y ? x : y;
}
2�br />#include <stdio.h>
void chline(char ch, int i, int j);
int main(void)
{
chline('$', 3, 5);
return 0;
}
void chline(char ch, int i, int j)
{
int index;
for(index = 1; index < i; index++)
putchar(' ');
for(index = 1; index <= j - i + 1; index++)
putchar(ch);
}
3�br />#include <stdio.h>
void chline(char ch, int col, int row);
int main(void)
{
chline('$', 3, 5);
return 0;
}
void chline(char ch, int col, int row)
{
int i, j;
for(i = 0; i < row; i++)
{
for(j = 0; j < col; j++)
putchar(ch);
putchar('\n');
}
}
4�br />#include <stdio.h>
double computer(double a, double b);
int main(void)
{
printf("%.2få’?.2fçš„è°å‡å€¼æ˜¯åQ?.3f\n", 0.3, 0.5, computer(0.3, 0.5));
return 0;
}
double computer(double a, double b)
{
double result;
result = 1 / ((1/a + 1/b) / 2);
return result;
}
5�br />#include <stdio.h>
void larger_of(double *, double *);
int main(void)
{
double x = 23.3;
double y = 34.4;
printf("Originally x = %.1f; y = %.1f\n", x, y);
larger_of(&x, &y);
printf("Now x = %.1f; y = %.1f\n", x, y);
return 0;
}
void larger_of(double * u, double * v)
{
double temp;
temp = *u > *v ? *u : *v;
*u = temp;
*v = temp;
}
6ã€ï¼ˆ½W¬ä¸€‹Æ¡ç 的程åºè¯»å–到æ¢è¡Œ½W¦çš„æ—¶å€™ä¹Ÿä¼šæ‰“å°å‡ºæ¥ï¼Œä¼šç»™äººçœ‹ä¸æ˜Žç™½çš„æ„Ÿè§‰åQŒçƒ¦æ€§æŒ‰[Enter]键的时候就退出åó@环,ä¸è¦è¯Õdˆ°EOFåQ?br />#include <stdio.h>
#include <ctype.h>
void printchar(char ch);
int main(void)
{
char ch;
printf("误‚¾“å…¥è¦åˆ†æžçš„东西:\n");
while((ch = getchar()) != EOF)
{
printchar(ch);
}
return 0;
}
void printchar(char ch)
{
if(isalpha(ch))
{
printf("%c %d\n", ch, toupper(ch) % 'A' + 1);
}
}
修改之åŽåQŒç¨‹åºå¦‚下:
#include <stdio.h>
#include <ctype.h>
int show_c_location(char ch);
int main(void)
{
char ch;
printf("Please enter some characters: \n");
while((ch = getchar()) != '\n')
printf("%c-%d ", ch, show_c_location(ch));
return 0;
}
int show_c_location(char ch)
{
int result;
if(isalpha(ch))
result = toupper(ch) - 'A' + 1;
else
result = -1;
return result;
}
7�br />#include <stdio.h>
double power(double n, int p);
int main(void)
{
double x, xpow;
int exp;
printf("Enter a number and the positive integer power");
printf(" to which\nthe number will be raised. Enter q");
printf(" to quit.\n");
while(scanf("%lf%d", &x, &exp) == 2)
{
xpow = power(x, exp);
printf("%.3g to power %d is %.5g\n", x, exp, xpow);
printf("Enter next pair of numbers or q to quit.\n");
}
printf("Hope you enjoyed this power trip -- bye!\n");
return 0;
}
double power(double n, int p)
{
int i;
double result = 1;
if(n != 0)
{
if(p > 0)
{
for(i = 1; i <= p; i++)
result *= n;
}
else if(p < 0)
{
for(i = 1; i <= -p; i++)
result *= (1 / n);
}
else
result = 1;
}
else
{
if(p == 0)
result = 1;// 0çš?‹Æ¡æ–¹æ˜¯ä¸€ä¸ªæœ‰äº‰è®®çš„æ•°åQŒæœ¬é¢˜è®¤ä¸ÞZ¼šå¾—到1
else
result = 0;
}
return result;
}
8�br />#include <stdio.h>
double power(double n, int p);
int main(void)
{
double x, xpow;
int exp;
printf("Enter a number and the positive integer power");
printf(" to which\nthe number will be raised. Enter q");
printf(" to quit.\n");
while(scanf("%lf%d", &x, &exp) == 2)
{
xpow = power(x, exp);
printf("%.3g to power %d is %.5g\n", x, exp, xpow);
printf("Enter next pair of numbers or q to quit.\n");
}
printf("Hope you enjoyed this power trip -- bye!\n");
return 0;
}
double power(double n, int p)
{
double result = 1;
if(n != 0)
{
if(p > 0)
result = n * power(n, p-1);
else if(p < 0)
result = (1/n) * power(n, p+1);
else
result = 1;
}
else
{
if(p == 0)
result = 1;// 0çš?‹Æ¡æ–¹æ˜¯ä¸€ä¸ªæœ‰äº‰è®®çš„æ•°åQŒæœ¬é¢˜è®¤ä¸ÞZ¼šå¾—到1
else
result = 0;
}
return result;
}
9�br />#include <stdio.h>
void to_base_n(unsigned long n, int range);
int main(void)
{
unsigned long number;
int range;
printf("误‚¾“å…¥è¦è½¬æ¢çš„æ— ½W¦å·æ•´æ•°å’Œæ‰€è§„定的进制数åQ?nbsp;\n");
while(scanf("%lu %d", &number, &range) == 2)
{
if(range >= 2 && range <= 10)
{
printf("æ— ç¬¦åäh•´æ•?luè½¬æ¢æˆ?d˜q›åˆ¶æ•îCØ“åQ?nbsp;", number, range);
to_base_n(number, range);
putchar('\n');
printf("误‚¾“å…¥è¦è½¬æ¢çš„æ— ½W¦å·æ•´æ•°å’Œæ‰€è§„定的进制数åQ?nbsp;\n");
}
else
printf("所规定的进制数的范围是2~10åQŒè¯·è¾“å…¥æ£ç¡®çš„æ•°å—\n");
}
printf("Done!\n");
return 0;
}
void to_base_n(unsigned long n, int range)
{
int r;
r = n % range;
if(n >= range)
to_base_n(n / range, range);
putchar('0' + r);
return;
}
10ã€ï¼ˆé¢˜æ„ç†è§£ä¸æ¸…楚,借鉴CSDN——vs9841åŽŸä½œè€…çš„åšæ³•åQŒè„‘å太½W¨ï¼Œå®žåœ¨æƒ³ä¸å‡ºæ¥åQ?br />#include <stdio.h>
int Fibonacci(int n);
int main(void)
{
int n = 9;
printf("当nä¸?dæ—Óž¼Œæ–æ‡L¾U›_¥‘æ•°å€égØ“%d", n, Fibonacci(9));
return 0;
}
int Fibonacci(int n)
{
int a, b, i;
a = 0;
b = 1;
int sum;
if(n == 0)
return 0;
if(n == 1)
return 1;
else
{
for(i = 2; i <= n; i++)
{
sum = a + b;
a = b;
b = sum;
}
return sum;
}
}
æ€È»“åQšæ€ÖM½“æ¥è¯´¾~–程¾lƒä¹ 相对以往æ¥è¯´è¦ç®€å•了åQŒä½†½W?0é¢˜æ²¡æ˜Žç™½ä»€ä¹ˆæ„æ€ï¼Œæ‰€ä»¥åªèƒ½å€Ÿé‰´åˆ«äh的了åQŒçœŸæ˜¯å¤©ä¸‹æ–‡ç« 一大抄åQ?img src ="http://www.aygfsteel.com/BeautifulMan/aggbug/428322.html" width = "1" height = "1" />
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