jdbc url: 詳細屬性可參考
Eg: jdbc:mysql://localhost:3306/test?user =root&password=&useUnicode=true&characterEncoding=utf8
mysql URL: mysql -uroot -p --default-character-set=utf8
這就重點說下:SHOW
1. 查看全部庫支持字符 如:'gb%' -gbk,gb2312
SHOW CHARACTER SET LIKE '%' ;
2. 查看列
show columns from user from mysql ;
show columns from mysql.user ;
desc mysql.user ;
//簡化
//更方便的 查看 列名 模糊查詢列名為 'Select%' (desc information_schema.columns 還有更多驚喜)
select column_name from information_schema.columns where column_name like 'Select%' ;
3. 查看數據庫,表結構;當然你們也可以仿照下此再建自己的庫,表
show
show create database information_schema"G
show create table mysql.user"G
4.權限查看
SHOW GRANTS FOR 'root'@'localhost';
.....(詳細參考 )
這就上寫自己一些有感覺的sql :參考
1.只查詢重復 Eg:
insert into c values ( 1 ),( 2 ),( 3 ),( 4 ),( 3 ),( 5 ),( 6 ),( 1 );
結果:
select id from c group by id having count (id) > 1 ;
2.報表查詢橫向輸出 Eg:
Create table d(id int,name varchar(50));
insert into d values(1,'gly');
insert into d values(2,'ptgly');
insert into d values(3,'ybgly');
insert into d values(4,'ptgly');
insert into d values(5,'ybgly');
+---+-----+------+
|gly |ptgly|ybgly|
+---+-----+------+-
|1 |2 |2 |
+---+-----+------+
sum ( case when name = ' gly ' then 1 else 0 end ) as gly ,
sum ( case when name = ' ptgly ' then 1 else 0 end ) as ptgly ,
sum ( case when name = ' ybgly ' then 1 else 0 end ) as ybgly
from d ;
3.復雜組合查詢
create table table_a (No int, No2 int,num double,itime date);
insert into table_a values
(1234,567890,33.5,'2004-12-21'),
(1234,598701,44.8,'2004-11-21'),
(1234,598701,45.2,'2004-10-01'),
(1234,567890,66.5,'2004-9-21'),
(3456,789065,22.5,'2004-10-01'),
(3456,789065,77.5,'2004-10-27'),
(3456,678901,48.5,'2004-12-21');
按月統計銷售表中貨物的銷售量數
查詢結果如下:
No, No2 , 九月, 十月,十一月,十二月
1234,567890, 66.5 , 0 , 0 , 33.5
1234,598701, 0 , 45.2, 44.8, 0
3456,789065, 0 , 100, 0 , 0
3456,678901, 0 , 0, 0 , 48.5
-----------------------------------------------------------------------
//這個 例子很好 哦!報表可以一句sql 得出!
select NO,NO2,
sum ( case when itime like ' 2004-%9% ' then num else 0 end ) as 9M,
sum ( case when itime like ' 2004-10% ' then num else 0 end ) as 10M,
sum ( case when itime like ' 2004-11% ' then num else 0 end ) as 11M,
sum ( case when itime like ' 2004-12% ' then num else 0 end ) as 12M
from table_a group by no,no2 order by no,no2 ;
4.字符集子層關系
1 a
2 b
11 c
(代碼11表示為1的下級)
我要通過一條句子,得出如下結果:
Create table TabTest(t_Code varchar(10),t_Name varchar(10));
insert into TabTest values('1','a');
insert into TabTest values('2','b');
insert into TabTest values('11','c');
--------------------------------------------------------------
case
when exists ( select 1 from tabtest tt2
where tt2.t_code like CONCAT(tt1.t_code, ' % ' ) and
tt2.t_code <> tt1.t_code ) then ' you '
else ' wu '
end ) as you_wu
from tabtest tt1 ;
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